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1. You don't have to diffuse the acid through the emulsion, only the proton, which is the smallest of all ions. I have seen the rate of pH drop when using acid on alkaline films. It is virtually instantaneous on a wet film. Today's thinner films make acidification very rapid. How was this tested? Among other things we coated /gel/dummy emulsion/indicator dye/support and then looked at the spectrum of the indicator dye vs time. We also used a surface pH meter but that was too slow!
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PE
Except under very special conditions you cannot have protons diffusing alone without also having diffusion of a counter ion (an ion of negative charge) in the same direction or diffusion of an ion of the same charge in the opposite direction.
The reason is because you must maintain electrical neutrality, or at least a very close approximation to electrical neutrality. For example, if diffusion of the proton gets too far ahead of diffusion of the counter ion what happens is the build up of an electrical field with opposes the concentration gradient and cuts off further diffusion. (To put it in terms the electrical engineers use when discussing transport of charge carriers in a semiconductor, the drift current opposes the diffusion current.)
One can estimate how much unipolar diffusion is allowed. Suppose that an emulsion were 10 microns thick. Further suppose that the relative dielectric constant of the wet emulsion approximates that of water (i.e. ~80). Further suppose that the pH of the emulsion drops from about 9 to about 7. I think these are all conservative assumptions as emulsions are, I think, usually a little thicker than this, the dielectric constant of the emulsion will be somewhat less than the dielectric constant of water, and the drop in pH for an acid wash will be greater than indicated above.
Next, suppose for sake of discussion that the diffusion is nearly unipolar, i.e. dominated by proton transport. under the assumptions discussed above one can calculate the charge imbalance built up in the emulsion and estimate the voltage induced by this charge imbalance. It works out to about 10 volts.
It is impossible for such a large voltage to be built up by diffusion. The most you can get is something of the order of thermal energy (about 0.025 electron, or about 40 times lower than the 10 volts implied by the calculation above). Therefore, unipolar diffusion of hydrogen ions cannot be a dominant process in a stop bath process. Therefore, diffusion must be ambipolar and therefore determined in large part by the diffusion coefficient of the counter ion. This diffusion coefficient will not be vastly different from the diffusion coefficients of developer molecules. Therefore although diffusion of the acid into the emulsion may be faster than diffusion of developer from the emulsion, it is not likely to be even an order of magnitude faster than diffusion of the developer, or in other words it will be on the same general time scale as diffusion of the acid.
I am not contradicting your claim that diffusion of acid into the emulsion will be fast. What I am saying is that diffusion of developer out of the emulsion will also be fast. However, there is also a possible curve ball mother nature may throw at us. If the developer becomes adsorbed or bound to the gelatin molecules or other emulsion components this could slow the transport of developer from the emulsion.