I think I have got a
resumé of the conclusions so far.
H
m for black and white film is an empirical, observed data. If the film is ISO rated, let's say ISO 100, then we know that H
m is 8 / ISO and so for each ISO H
m is a quantity which is known a priori, in this case 0.08 lux.seconds, or LogH
m = -2.1.
Now if H
g is defined as H
m * 10, and this definition must occur somewhere in the ISO standard, although I am not sure light meter makers honour it, then in this ISO 100 case H
g = 0.8 lux.seconds, or LogH
g = -1.1.
So there is, in black & white negative, a fixed relation between ISO and H
m, a fixed relation between H
m and H
g (ten times, LogH 1, 3.3 EV) and therefore a fixed relation between ISO and H
m.
Re-reading the thread I understood that RobC simply and automatically wants to apply this simple relation to slide film. So he expects, or should I say he demands, an H
mR (R for Reversal) which is, simply, LogH 1.0 less exposure than metered. Now, either I am not in good command of this language, or RobC is not very good at making his thought clear, or both.
Rob, forget the B&W relation between H
m and H
g when you deal with slides. They are not 3.3 EV apart. They are very close, because the speed point, in slides, is defined in a totally different way. What the relation is, for slides, between H
mR and H
g, varies depending whom you ask to, but it is entirely different
A light meter manufacturer should, in theory, aim at creating an exposure of LogH -1.1 when the light meter is set at ISO 100.
The fact that Minolta states (but it would be better to read the original terms of the letter) that they aim to reach a density of LogH -1.0 seems to show that they, from the start, choose not to calibrate according to ISO standard. The speed point being fixed, it means they chose to place the H
g point at LogH 1.1 higher, not LogH 1.0 higher, than H
m.
What role play K and b in this? They enter into the calculation of the distance between H
m and H
g.
The fixed relation of "ten times" stems from the formula
H
g = [(b * K) / 0.8] * H
m
if we populate the equation with b = 0.65, the number which is used generally in ISO standards according to Conrad, and K = 12.5, we obtain 10.16, in logarithmic terms 1,007. So the "ten times rule" depends from these assumptions: b = 0.65 and K = 12.5.
If we now substitute K = 14.0, which is the declared value adopted by Minolta, and keep b = 0.65, the "distance factor" becomes 11,375 and LoghH = 1,056. That is exactly 1/6 EV (because it is 0.05 LogH) different than the normal distance factor of 10.16.
That means, in turn, that Minolta must have chosen a b very similar to 0.72 because that is the value which, coupled with K = 14 which Minolta declares, and with a target density of LogH = -1.0 (instead of -1.1) which Minolta declares, creates a "distance" between H
m and H
g of 3.6 EV (LogH 1.1), or 1/3 EV more than the normal 3.3 EV.
It's an overall exposure 1/3 EV different from what one might expect, half due to EV = 14 (instead of 12.5) and half due to b = 0.72 (instead of 0.65).
Maybe the original letter from Minolta to RobC also mentions the b factor (?)