Kodak grey card usage

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Diapositivo

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If I read correctly Jeff Conrad, Exposure Metering - Relating Subject Lighting to Film Exposure, 1998, 2003, Page 12, the density created by a light meter exposure on a slide developed according to the manufacturer directions should always be 0.91. That is the "middle grey point" on the slide.

That should correspond to an opacity of around 8.2, and a transmission of around 12%.

I think one of the three hypothesis apply;
1) Light meters are calibrated to 12%;
2) Light meters are calibrated to "grey card" 18% which also is "perceptual middle grey of human vision" (given a black blackpoint and a white whitepoint) but for some unknown perceptual reason a 12% transmission of a slide works well in rendering an 18% grey (due to some problems, for instance, in reaching a reasonable white point during projection, so that the perceptual middle between DMin and DMax is actually at that point fixed by the slide);
3) I did not understand anything of Conrad, of middle grey on slide film, and possibly of life in general :smile:
 
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As usual when you are asked to explain or give proof you refuse. I didn't ask for other peoples papers which are peer reviewed, I asked for yours and with your usual eavasive response you have tried to fob me off by quoting someone elses peer reviwed work.

And not only someone elses but as I 've already pointed out, they are very very old. i.e. the data used is out of date with regard to flare in modern lenses and you are now trying to obfuscate that which is your standard way of trying hide what you don't know. Mees and Jones work is at least 75 years old and you are quoting it as your reference data.

You have not found a single error in what I've said but once again are trying to start an argument about it and presenting your own out of date findings about it. You haven't given a single reposnse worth reading.

Once again, explain how it is that there is no flare adjustment when the film speed and K factor are equal.
And please present references to peer reviews of your own work. Failure to give satisfactory answers will tell us all we need to know.

And in your ignorance you have once again missed the whole point which is that if you have calibrated your exposure, dev and printing you don't need to know any of the crap you keep posting about ancient and out of date scientific derivations.

A practical evaluation trumps everything your plagiarised scientific formula are trying to prove.

All I've done is start a topic providing the instructions on how a kodak grey card should be used, or at least how it was with the card I have.

And yes I have put some numbers into the standard reflection meter formula to see what is really happening and you have a problem with that. Anyone with an ounce of sense trying to understand a problem would do exactly what I've done and you want to infer its meaningless. That tells us a lot about you.

I know exactly what I get on film becasue I've calibrated to my own standard which I'm not forcing on anyone like you are trying to do. I know if I meter anything I can place it on any zone and it works because I've tested it. I'm not in the slightest bit interested in disappearing up my own anal tract by trying to convert my meter readings into log values that you want me to give you so that you can tell me they don't match yours. Why would I waste my life on doing something so purile. I use my own standard calibration which I've repeated often on the forum so it should be blindingly obvious to you that it wouldn't mean anything to you since you are so blinkered and it would be pointless comparing to your numbers.

You know I'm not interested in hearing what you have to say but you can't help yourself from trying to force it on me. I'm not interested. I hope that has registered.

I've read it all before from the people who actually did the original research and I know enough about it to know things have changed in the last 75 years since the research was done, especially with regard to lens flare. I think you are stuck in 1940s and the previous 50 years research.

I have an idea, why don't you please do us both a favour and put me on your ignore list instead of inventing meaningless diversions to try and hide what you can't explain.

Flare at Hg is built into the K equation so the value of K has a flare factor in it.
 

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My reaction to a lot these equations kicked about, and somewhat vitriolic debates...
  • about C and K values,
  • about considerations for lens flare,
  • about these various analytical means of having the conflicting claims proven
...The aeronautical engineer has all of the equations and proofs that the bumblebee cannot possibly fly. What does the theory prove?...
We only need to look at a bumblebee to see that it is engineers' theories are what are NOT FLYING!
Meanwhile the pragmatic bumblebee nevertheless flies, pollinates flowers, gets food to take home, and the colony is happy.

Curves are great and densitometry readings are one way to assure your exposure and your processing are delivering what you should be getting for results. But they do not always seem to agree...Bumblebee theory demonstrated. Sometimes we need to set aside the theory and apply the theory to practical benefits, the enjoyment of our hobby/craft, because the theory gets in the way of enjoyment and causes too much angst.

I am a photographic pragmatist, I want to recreate the bumblebee's ability to fly (in spite of what the engineer's equations seem to prove). Photographically, I seek a consistent means of putting the middle tone 'in between apparent white and apparent black', and sometimes I do need tonal fidelity across the range of tonal steps, but at other times I am more artistically driven and I care not about full fidelity but only enough fidelity for a viewer to figure things out simply with a glance at the photo.

I present this to illustrate my point about the pragmatic application (yes, they are digitally taken, but they illustrate my point about abandonment of too much theory). For the curve compulsive, shot 2 is with linear response, shot 3 is 'moderate contrast S curve', shot 3 is with an exaggerated high contrast S curve...and yet the first four shots have placement of 18% reflectivity square of the Macbeth card at 50% tonal value. Shot 5 has 18% reflectivity square of the Macbeth card darker than we expect ('underexposed)'.
tonal%20accuracy_zpsggvghey1.jpg


Photo 1, an ordinary color 'snapshot'. Photos 2, 3, and 4 illustrate pragmatism that middle grey is 'in the middle' between perceived black and perceived white. Difference in contrast (perhaps different S curves for different contrast emulsions) make the portayal of 'white' and 'black' and other tones fit or not fit expectations of where the 'real' tone is vs. where the film/print paper portrays them. But we all agree that middle tone is somewhere in between the tonal extremes.
Photo 5 has some pretty dramatic alterations not only to the S shape of the curve but also where 'middle grey' shows up, it is 'underexposed' or 'too dark' and we no longer can agree upon where is the 'middle tone' in the shot (unless we count squares with our familiarity with the MacBeth card). So photos 1-4 all succeed in conveying to viewers correctly what we intend, in spite of the presentation of the toe and shoulder messing with some of the tones. But for me, the pragmatist, photo 5 falls flat on its face. that is, my use of the grey card did not achieve my goal in photo 5 because I fail to know what, if anything, is tonally reasonable in its accuracy...I can see what I believe to be white, I can see what I believe to be black, but my tonal perception of the scene is confused with uncertainty
 
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Diapositivo, here is a quick answer for you.


The speed of B&W negative and color reversal film are determined at critical points. With B&W negative film it has to do with the limiting gradient of the film curve. This defines the minimum exposure which can yield a quality print. When the contrast parameters of the ISO standard are maintained, this point falls approximately one stop to the left of the exposure for the fixed density speed point (Hm where the density equals 0.10 over Fb+f). To calculate B&W film speed Hm is plugged into the equation S = 0.80/Hm where 0.80 is known as the speed constant. Using this equation, the value of S is 1/3 stops slower than what Hm would otherwise indicate. This is difference is to adjust for the color temperature of the sensitometric exposure; however, the idea that the film speed value can be different from the speed point is important. To calculate what the Hm should be for any speed, the equation is 0.80 / film speed = Hm.

BW and Color Reversal Speed Determination w Delta-X Equation.jpg


With reversal color film, the speed point is found in the “middle” of the curve. Please refer to the example. Point HF is located on the curve 0.2 above the minimum density. The exposure value HR is the geometric mean between HF and HS. The speed equation is S = 10 / HR. Please note that the nomenclature in this example is outdated.

Sometime in the 70s or early 80s the speed equation changed from 8/HR to 10/HR thus increasing the speed of reversal film by 1/3 stop. The way the speed point was determined didn’t change, just the speed constant. It’s all about the relationship between the speed point and Hg. In this example, we know where HR was determined and we know where Hg should fall. At one time this was the same point with reversal color film, but it was decided to reduce the overall exposure. Now Hg falls 1/3 stop below HR.

The exposure meter wants to place the exposure at Hg. This relationship can be determined with the equations Hg/Hm for B&W film and Hg/HR for reversal color film. For B&W this value is 10. For color reversal it’s 0.8. In the previous incarnation it was 1 which means the speed point for reversal color film was the same point as where the exposure wanted to place Hg. The equation can also use the speed constants and the value for Eg.

Eg can be thought of as the value of exposure striking the film plane if the shutter speed is at one second. From this Hg can be determined with the equation Eg * 1/ISO = Hg. Eg as a constant is referred to as K1 in the exposure meter standard or in some papers as P. So the equation can be reduced to Hg = 8/ISO.

8/100 = 0.080 lxs 8/125 = 0.064 lxs 8/400 = 0.020 lxs

If it’s determined there needs to be a change where Hg should fall on the film plane, the meter doesn’t need to be adjusted, nor the method of determination the speed point. All that needs to be changed is the speed constant. This will change the speed number and consequently placement of Hg by the exposure meter.


Dunn - Calibration Levels for Exposure Estimating Devices.jpg
 
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Bill Burk

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My garage door from across the street gives me a large dark target of several degrees, so it's not that the spot has a little intrusion of the surrounds... You'll see the light reading gradually drop to a more accurate reading the closer you get...

I can't prove where you are right (for example the fact that the metered point is near the middle of a range of 6 stops), without demonstrating how flare works into the calculation. Sure you can say that the film speed was chosen to relate to the meter in a way that deals with flare... so you don't need to know it.

But discussing flare will help with the proof.
 
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Contrast Indexes - Kodak Normal.jpg
Here's a chart that Dick Dickerson gave me. It has the Subject Luminance Range on top and the Paper grades on the side. For an average scene of 7 1/3 stops to be printed on a grade 2 paper with an LER of 1.05, Kodak has the CI as 0.58. This is Kodak's normal. CI is a particular method of average gradient. Average gradient can be determined using the equation Rise over Run. So 1.05 / 2.20 = 0.477. Why the difference? Flare. The aim CI for a given Luminance range to fit onto a given grade should be determined as LER / LSLR - Flare. So 1.05 / (2.20 - 0.40) = 0.58. Film processing is based on the optical image, so for an average 7 1/3 stop scene, the processing is for a 6 stop camera image.
 

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That sure looks like a chart Stephen Benskin gave me that I refer to every time I develop a roll of film.
 

Bill Burk

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I present this to illustrate my point about the pragmatic application (yes, they are digitally taken, but they illustrate my point about abandonment of too much theory). For the curve compulsive, shot 2 is with linear response, shot 3 is 'moderate contrast S curve', shot [4] is with an exaggerated high contrast S curve...

OK. Shot 3 looks like a fair simulation of the tone distributions for gray that I would expect from film. I wouldn't call myself curve compulsive (though I guess what I've written contradicts how my ego sees myself), but you can see about how much difference I'm talking about when you look at the differences between those two shots (2 and 3).
 

Diapositivo

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the formula for a reflected meter is:

2Ev = (B*S)/K

EV = Exposure Value
B = luminance in cd/m2
S = ISO Film Speed
K = K factor = 12.5 (using 12.5 equates to multiplying by 8% (0.08) hence B*S*0.08)

So
0.5 * 100 * 0.08 = 4 = EV2

4 = 2Ev so to convert from that to EV you must take the log2 of 4 which = 2

so you get

0.5 * 100 * 0.08 = 4 = EV2
16 * 100 * 0.08 = 128 = EV7

a difference of 5 stops

Rob, it seems to me that that would work with any K factor. For instance if K factor was 5, you would have the formulas:
0.5 * 100 * 0.2 = 10 = EV 3.33
16 * 100 * 0.2 = 320 = EV 8.33

The same difference of 5 stops, whichever K factor we choose.
 

Diapositivo

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My reaction to a lot these equations kicked about, and somewhat vitriolic debates...
  • about C and K values,
  • about considerations for lens flare,
  • about these various analytical means of having the conflicting claims proven
...The aeronautical engineer has all of the equations and proofs that the bumblebee cannot possibly fly. What does the theory prove?...
We only need to look at a bumblebee to see that it is engineers' theories are what are NOT FLYING!
Meanwhile the pragmatic bumblebee nevertheless flies, pollinates flowers, gets food to take home, and the colony is happy.

Curves are great and densitometry readings are one way to assure your exposure and your processing are delivering what you should be getting for results. But they do not always seem to agree...Bumblebee theory demonstrated. Sometimes we need to set aside the theory and apply the theory to practical benefits, the enjoyment of our hobby/craft, because the theory gets in the way of enjoyment and causes too much angst.

I am a photographic pragmatist, I want to recreate the bumblebee's ability to fly (in spite of what the engineer's equations seem to prove). Photographically, I seek a consistent means of putting the middle tone 'in between apparent white and apparent black', and sometimes I do need tonal fidelity across the range of tonal steps, but at other times I am more artistically driven and I care not about full fidelity but only enough fidelity for a viewer to figure things out simply with a glance at the photo.

I present this to illustrate my point about the pragmatic application (yes, they are digitally taken, but they illustrate my point about abandonment of too much theory). For the curve compulsive, shot 2 is with linear response, shot 3 is 'moderate contrast S curve', shot 3 is with an exaggerated high contrast S curve...and yet the first four shots have placement of 18% reflectivity square of the Macbeth card at 50% tonal value. Shot 5 has 18% reflectivity square of the Macbeth card darker than we expect ('underexposed)'.
tonal%20accuracy_zpsggvghey1.jpg


Photo 1, an ordinary color 'snapshot'. Photos 2, 3, and 4 illustrate pragmatism that middle grey is 'in the middle' between perceived black and perceived white. Difference in contrast (perhaps different S curves for different contrast emulsions) make the portayal of 'white' and 'black' and other tones fit or not fit expectations of where the 'real' tone is vs. where the film/print paper portrays them. But we all agree that middle tone is somewhere in between the tonal extremes.
Photo 5 has some pretty dramatic alterations not only to the S shape of the curve but also where 'middle grey' shows up, it is 'underexposed' or 'too dark' and we no longer can agree upon where is the 'middle tone' in the shot (unless we count squares with our familiarity with the MacBeth card). So photos 1-4 all succeed in conveying to viewers correctly what we intend, in spite of the presentation of the toe and shoulder messing with some of the tones. But for me, the pragmatist, photo 5 falls flat on its face. that is, my use of the grey card did not achieve my goal in photo 5 because I fail to know what, if anything, is tonally reasonable in its accuracy...I can see what I believe to be white, I can see what I believe to be black, but my tonal perception of the scene is confused with uncertainty

Although pictures 2 and 3 look almost the same in my monitor I certainly agree with the premises, the method, and the conclusions!
 

Diapositivo

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Diapositivo, here is a quick answer for you.


The speed of B&W negative and color reversal film are determined at critical points. With B&W negative film it has to do with the limiting gradient of the film curve. This defines the minimum exposure which can yield a quality print. When the contrast parameters of the ISO standard are maintained, this point falls approximately one stop to the left of the exposure for the fixed density speed point (Hm where the density equals 0.10 over Fb+f). To calculate B&W film speed Hm is plugged into the equation S = 0.80/Hm where 0.80 is known as the speed constant. Using this equation, the value of S is 1/3 stops slower than what Hm would otherwise indicate. This is difference is to adjust for the color temperature of the sensitometric exposure; however, the idea that the film speed value can be different from the speed point is important. To calculate what the Hm should be for any speed, the equation is 0.80 / film speed = Hm.

View attachment 153312

With reversal color film, the speed point is found in the “middle” of the curve. Please refer to the example. Point HF is located on the curve 0.2 above the minimum density. The exposure value HR is the geometric mean between HF and HS. The speed equation is S = 10 / HR. Please note that the nomenclature in this example is outdated.

Sometime in the 70s or early 80s the speed equation changed from 8/HR to 10/HR thus increasing the speed of reversal film by 1/3 stop. The way the speed point was determined didn’t change, just the speed constant. It’s all about the relationship between the speed point and Hg. In this example, we know where HR was determined and we know where Hg should fall. At one time this was the same point with reversal color film, but it was decided to reduce the overall exposure. Now Hg falls 1/3 stop below HR.

The exposure meter wants to place the exposure at Hg. This relationship can be determined with the equations Hg/Hm for B&W film and Hg/HR for reversal color film. For B&W this value is 10. For color reversal it’s 0.8. In the previous incarnation it was 1 which means the speed point for reversal color film was the same point as where the exposure wanted to place Hg. The equation can also use the speed constants and the value for Eg.

Eg can be thought of as the value of exposure striking the film plane if the shutter speed is at one second. From this Hg can be determined with the equation Eg * 1/ISO = Hg. Eg as a constant is referred to as K1 in the exposure meter standard or in some papers as P. So the equation can be reduced to Hg = 8/ISO.

8/100 = 0.080 lxs 8/125 = 0.064 lxs 8/400 = 0.020 lxs

If it’s determined there needs to be a change where Hg should fall on the film plane, the meter doesn’t need to be adjusted, nor the method of determination the speed point. All that needs to be changed is the speed constant. This will change the speed number and consequently placement of Hg by the exposure meter.


View attachment 153313

Thank you very much!

I will try to digest all this and will certainly come back to you with questions (sorry about that! :smile: ).
 
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Here is the Ev for Sunny 16 or the exposure meter calibration equation.

Ev for Calibration A.jpg


If you want the average reflectance, simply divide I by B*pi. From the above example, we first have to convert I 7681*10.76 = 82648 and B is based on K which is rounded up from 12.478, so then B would equal 3194.

3194 * pi / 82648 = 0.121 or 12%
for 18%, B would need to be equal to 4735.
 
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If I read correctly Jeff Conrad, Exposure Metering - Relating Subject Lighting to Film Exposure, 1998, 2003, Page 12, the density created by a light meter exposure on a slide developed according to the manufacturer directions should always be 0.91. That is the "middle grey point" on the slide.

Sorry Diapositivo but that's not what 0.91 is referring to. His b is the same as q. q takes into consideration the light transmission characteristics of the camera's optical system. He is also using a slightly different value of b which is legitimate for depending on the lens and how it is being used, the value of q can differ. In this case he is using a different value for the angle of the image point from the axis of the lens. The standard uses 12%. Conrad uses unity or directly on the center axis of the lens. Hand held meters need to come up with an basic value of q that as Connelly writes, "because the objective is to assess the exposure required for an average scene it has been found that in practice the variations of q due to the causes mentioned can be allowed for by allocating specific values to the given parameters which give a single value of q satisfactory for the exposure determination of a large majority of scenes."

If you refer to my post on film speed and speed constants, you will notice that the relationship of the speed point to Hg for reversal color film is 0.80. Because Conrad is using a different value for b (q), his relationship is 0.91*Hg. That's all it means.

Please read one of Connelly papers found at http://64.165.113.140/content/benskin/ or you're just going to go round in circles. Calibration Levels of Films and Exposure Devices is a good place to start but as you are more interested in incident exposure meters, his The Incident Light Method of Exposure Determination might be the one you'd me more interested in.
 
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RobC

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Diapositivo,
As I said in a previous post, I thought that reflection meters use 100 speed as a baseline speed. The reason I thought this is that my Minolta Spot meter definitely uses 100 speed as some kind of baseline because in order to get a cd/m2 value from it, you must use speed 100 to get EV and then convert using a provided chart of numbers. But that may just be because there is only a chart for a 100 speed.
Anyway lets assume for now that a speed of 100 is a baseline for reflection meters internal processing and that the meter assumes a speedpoint of 0.1 above fb+fog. Then the reading given would produce 3 exposure stops more than the speed point requires as we determined in earlier post (16*100*0.08 = 128 = EV7). So infact 3 1/3 exposure stops above what we expect for fb+fog(0 exposure).
Well we know from the multitude of graphs produced (Bills example below is good), that using ISO speed and manufacturer recommended dev that for 3 1/3 stops of exposure we can expect a neg density of 0.6 including fb+fog for that point on B&W negative film. We also know that we require a negative density range of 1.3 for a full scale negative from a 7 1/3 stop subject brightness range. So if our subject is 7 1/3 stops range from black to white then we have 4 stops of subject brightness range above our lower 3 1/3 stops and we know that it will fit into the top 0.7log of our 1.3log full negative density range.
So that tells us that our meter, for a B&W negative film is placing the exposure 3 exposure stops up from speed point and 4 exposure stops down from 100% of the exposure range. 4 stops less than 100% is approx 6.25% of 100%.

So I conclude that if we metered a grey card we would expect it to be 3 exposure stops up from speed point which would be on a density of 0.6log of opacity including fb+fog assumming film is B&W negative, the meter is using 100 speed as baseline for its internal processing (which we don't know for sure) and manufacturers ISO speed and recommended dev are being used. And K = 12.5

The assumed meter baseline of 100 speed seems to fit what is actually happening so we'll go with that for now.

Borrowed from Bill, I hope he doesn't mind. I can remove if he does.
ZoneRulerGraphF.jpg



SLIDE FILM
check following carefully as I'm not 100% its right.
So what about slide film metered with a spot meter? Well slide film has a much steeper curve over a shorter subject brightness range so things will be different. I'll use Provia 100 as an example. It gets a bit tricky straight away becasue it depends where on the curve you pick as being black, as soon as the colour curves start to separate or somewhere else with less exposure where the curves have separated a little further. Well for the purposes of this example and using the fuji H&D curve for provia 100 I'll give 4 examples of where black may be considered:
Same meter as used for negative film which I think we are now fairly sure of how it works.

1 black is -3.0 LogH (lux seconds) = 0.001 lux seconds eposure
2 black is -2.0 LogH (lux seconds) = 0.01 lux seconds exposure
3 black is -1.0 (lux seconds) = 0.1 lux seconds exposure
4 black is -1.75 (lux seconds) = 0.178 lux seconds exposure

we just meter the subject whatever it is (maybe a grey card ) and reading from the fuji H&D curve we just look 3 + 0.1log speed point exposure stops to the right (1.0LogH shift to right) on the LogH exposure axis and read off the slide density above it so we get:

1 black is -3.0 LogH = 2.8 log slide density
2 black is -2.0 LogH = 1.0 log slide density
3 black is -1.0 LogH = 0.2 log slide density
4 black is -1.75 LogH = 0.75 log slide density

However, this is tricky because we can't judge by eye exactly what any of these dark colours are so we can't be sure where the tone will end up. And we know we must preserve the highlights on slide film.

So, what if we want a grey card to be slide density 0.75?
What we can do is meter something which we want to be just full white, this will give a reading which is shifted 1.0logH(3 1/3 stops) to right and be vastly overexposed well into the white. But knowing that we can close down by 3 1/3 stops + close down another 0.75logH (2 1/2 stops) to put our result on density 0.75 which is same as an 18% grey card. So meter just pure white and close down 5 5/6 stops.

Or alternatively you could meter a grey card which you know is 18% reflectance so is 2 1/2 stops less than white(18% is 2 1/2 stops less than 100%). This will then get 1.0logH (3 1/3 stops) over exposure (due to the way a spot meter works) so to bring it back down to what you metered you close down by 3 1/3 stops.

And that means roughly speaking that for slide film using a reflection meter with assumed baseline of 100 speed for internal processing and K = 12.5 you can meter anything you like and close down 3 1/3 stops and it will be fairly close to original tone assuming its on the straight line of the curve which a midtone such as a grey card should be. Different film curve shapes may well affect this so I think there will be some trial and error to get it spot on.

Please try out my theory for slide film and report back. Trying both metering white and metering grey card would be good. I think colour accuracy would be better metering white because you are not dependant on grey card angle which if you didn't get it right would throw off your exposure. Back of Kodak Grey card is white so would be a good target for test of theory but could be bright clouds or some such if it exists in the subject.

Fuji Provia 100 III H&D Curve
fuji-provia-100-III.jpg
 
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Diapositivo

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Sorry Diapositivo but that's not what 0.91 is referring to. His b is the same as q. q takes into consideration the light transmission characteristics of the camera's optical system. He is also using a slightly different value of b which is legitimate for depending on the lens and how it is being used, the value of q can differ. In this case he is using a different value for the angle of the image point from the axis of the lens. The standard uses 12%. Conrad uses unity or directly on the center axis of the lens. Hand held meters need to come up with an basic value of q that as Connelly writes, "because the objective is to assess the exposure required for an average scene it has been found that in practice the variations of q due to the causes mentioned can be allowed for by allocating specific values to the given parameters which give a single value of q satisfactory for the exposure determination of a large majority of scenes."

If you refer to my post on film speed and speed constants, you will notice that the relationship of the speed point to Hg for reversal color film is 0.80. Because Conrad is using a different value for b (q), his relationship is 0.91*Hg. That's all it means.

Please read one of Connelly papers found at http://64.165.113.140/content/benskin/ or you're just going to go round in circles. Calibration Levels of Films and Exposure Devices is a good place to start but as you are more interested in incident exposure meters, his The Incident Light Method of Exposure Determination might be the one you'd me more interested in.

I am slowly trying to study all this material. I signal that in the document "Calibration Levels of Films and Exposure Devices" page 189 is missing. The PDF goes from page 188 to page 190.

Happy Easter to everybody!
 
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I am slowly trying to study all this material. I signal that in the document "Calibration Levels of Films and Exposure Devices" page 189 is missing. The PDF goes from page 188 to page 190.

Happy Easter to everybody!
I'll try to upload a new version. Until then, here's the missing page. p 189.jpg
 

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So taking some sensible numbers we can start with a cd/m2 value of 16 which by itself would be EV4

...

Now lets try 32 as the value of cd/m2 read, which by itself would be EV5.

You are talking about luminance, Bv ... and it's not too hard to find notes which explain that Bv includes K

https://en.wikipedia.org/wiki/APEX_system

http://www.dougkerr.net/Pumpkin/articles/APEX.pdf

So for you to be able to take 16 and arrive at 4 K has to be 3.3333
16 cd/m2 = Bv 4 when K=3.3333
16 cd/m2 = Bv 2 when K=12.5

32 cd/m2 = Bv 5 when K=3.3333
32 cd/m2 = Bv 3 when K=12.5

This doesn't invalidate the other Ev numbers you were using in your illustration, because later when you multiply by 0.08 you establish K=12.5 so those Ev are correct. You might need to revisit your differences and conclusions.

My favorite formula that relates to this is: Ev = Av + Tv = Bv + Sv

I put in a few sensible values to that formula and noticed the discrepancy in Bv

f/1.4, 1/60 second, ISO 100...

Ev 7 = Av 1 + Tv 6 = Bv + Sv 5 ... and noticed Bv has to be 2

What's even more fun, if you enjoy working with the APEX system... you have a direct way to relate K to changes in Ev

To those trying to follow along, you need a Log2 calculator.

Here's one: http://logbase2.blogspot.com/2008/08/log-calculator.html
 
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RobC

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You are talking about luminance, Bv ... and it's not too hard to find notes which explain that Bv includes K

https://en.wikipedia.org/wiki/APEX_system

http://www.dougkerr.net/Pumpkin/articles/APEX.pdf

So for you to be able to take 16 and arrive at 4 K has to be 3.3333
16 cd/m2 = Bv 4 when K=3.3333
16 cd/m2 = Bv 2 when K=12.5

32 cd/m2 = Bv 5 when K=3.3333
32 cd/m2 = Bv 3 when K=12.5

This doesn't invalidate the other Ev numbers you were using in your illustration, because later when you multiply by 0.08 you establish K=12.5 so those Ev are correct. You might need to revisit your differences and conclusions.

My favorite formula that relates to this is: Ev = Av + Tv = Bv + Sv

I put in a few sensible values to that formula and noticed the discrepancy in Bv

f/1.4, 1/60 second, ISO 100...

Ev 7 = Av 1 + Tv 6 = Bv + Sv 5 ... and noticed Bv has to be 2

What's even more fun, if you enjoy working with the APEX system... you have a direct way to relate K to changes in Ev

To those trying to follow along, you need a Log2 calculator.

Here's one: http://logbase2.blogspot.com/2008/08/log-calculator.html

Ah Wikipedia where only the truth and accuracy can be found, a bit like the massive development chart :wink:

For example people keep writing Ev when it should be Ev. Why? becasue if you use Ev instead of Ev it implies from standard mathematical notation that v is a base number of E (function derived value of E) and it isn't in the formula I used and nor does my meta data explain itself as such. Take care with what you write or some pedant will try and suggest it's wrong.

I'm using the formula which minolta sent to me when I asked them a question about how their meters worked (except they use K =14) and not something I found in the dead sea scrolls.

I'm not going to complicate anything by introducing Bv. It's unecessary in the scope of this topic since the minolta supplied formula I'm using is not using it.
 
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Diapositivo

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RalphLambrecht

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using it perpendicular to lens axis is half the sequence of doing a lighting ratio test but I haven't bothered to read all of that.
If you have done proper film,dev, print claibration then you can just use your spot meter directly to get lighting ratios and placement of tones.
Exactly!
 
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