With the Zone System, you meter a target and stop down four stops. In the example below, the ISO speed of the film is 125. That means the exposure at 0.10 over Fb+f is 0.0064 lxs making 0.8 / 0.0064 = 125. The metered exposure is 8 / 125 = 0.064. Four stops down from the metered exposure is the exposure 0.0041 or too low for the 0.10 density speed point. In order for the four stops down exposure to fall at 0.10 over Fb+f it requires 2/3 stop more exposure. One way to do this is to rate the 125 speed film at 80.
Would this mean if I translated the ISO speed point into a zone would it lie at zone 0 1/3 from the view point of the ZS?
I think trying to approach it this way can cause a lot of needless confusion.
I think getting a yes, or no answer would make it easier to understand.
Would this mean if I translated the ISO speed point into a zone would it lie at zone 0 1/3 from the view point of the ZS?
In order for the four stops down exposure to fall at 0.10 over Fb+f it requires 2/3 stop more exposure. One way to do this is to rate the 125 speed film at 80.
Only, the horizontal axis in Schaefer is not divided in 0.2 log exp units, as is presented by your graph, but is shown with major divisions at 0.3 log exp units (as in The Negative), the attachment shows the differences; also, there would be a Zone 0 indicated without an exposure unit applied. The log value of each exposure unit, starting at Zone I, jives nicely with zone divisions at 0.3 units of log exposure, the most important log value, of course, being log10 of 2 = 0.3. I just think it makes looking at curves easier, probably a trivial thing to mention to most, but that's just my opinion.
Would this mean if I translated the ISO speed point into a zone would it lie at zone 0 1/3 from the view point of the ZS?
A quick look through Schaefer's book shows that while he does have coordinates at Δ0.30 log intervals (actually labeled in Zones), he also used graphs with the coordinates labeled every Δ0.20 logs.
View attachment 65814
I came to this conclusion because of the lower ISO rating with the ZS. Well I just going to have to reread all this and think. It is starting to hurt.Well, no it really wouldn't. I'll try to put something together. In the mean time, what part of my explanation so far don't you understand?
What makes you think it would?
Maybe this will help.
View attachment 65880
What is basically happening is the Zone System test changes the ratio between the speed point and the metered exposure from the ISO's Δ1.00 (10x) to the Zone Systems Δ1.20 (16x). It isn't so much about determining film speed.
The examples deal with exposure in testing and not exposure placement in use. Flare still has to be added to the mix.
I also assert that for Zone System testing, you also develop for less time. This moves the 0.1 density further to the right (slower).
ZS normal is around CI 0.58. Using a fixed density method for EI determination, the difference between the ISO contrast parameters and the Zone System method of determining contrast, the fixed density point will shift slightly to the left. Probably not a full Δ0.10 but contributing as Bill said. With the fractional gradient method / Delta-X criterion, there would be negligible difference in speed.
The range of EIs from most Zone System testing is generally from 1/2 to 1 stop slower than the ISO speed. I believe imprecision of using the camera's f/stop in ZS testing and experimental error are the major causes of the variance.
So theoretically if we keep the ISO speed, add in flare we could be alright.
If I look at the latest graph from Stephen we need to decrease exposure using the ZS model, but we would need to increase development to compensate the higher zones.
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