OK, I'm where I can measure my camera now, and I did make one miscalculation -- I should be measuring the size of the front lensboard frame, rather than just the lensboard. So the physical distance the top moves is greater, but not a lot. Using the revised size (8" frame, as opposed to 5" lensboard), I estimate the top of the frame will be 0.080" further away from the back than the bottom. I had no idea such a small misalignment (0.58 degrees) shifted the plane of focus 45 degrees. Your run-of-the-mill spirit level cannot resolve much less than 0.3 degrees; if you want the plane of focus to be within 10 degrees of parallel of the back, the front frame has to be within 0.1 degrees of parallel (assuming the same focusing distance and lens). I hope I have this math wrong ...
I have no idea what you are talking aboutI don't believe that 1/2 a degree shifts the plane of focus 45 degrees. I shoot in a studio situation all day every day and I would venture to guess that 75% of my tilts are less than 5 degrees and that is not to shift the focus 45 degrees, more like 10 - 20 degrees. I am more of a visual person than a math person so I just use what the ground glass tells me to use. Anyway, I have to agree with an earlier poster who said you were overthinking it. Using the DOF Master app on my iphone: 8x10 film with a 300mm lens at f16 the hyperfocal distance is 93.3' which takes care of anything from 46.6' to infinity. I guess I'm lazy and I let others do my math for me.
Regardless, have fun and keep us posted on how everything turns out.
I do promise to post an update when the project is done. But for the time being, I want to say I appreciate your candor. I think there are a lot of people who don't believe 1/2 degree shift of the lensboard can move the plane of focus 45 degrees. I was among them, which was the impetus behind my initial post. I was hoping someone would demonstrate it isn't so; that hasn't happened. Without going into the trig, a mental experiment demonstrates the "leverage" at work (and if I am misconstruing the Scheimpflug rule, I hope someone will set me straight):
The point of focus is 100 ft in front of the film plane. If you want a 45 degree plane of focus through that point, you extend that plane toward the camera until it intersects with the vertical film plane. You now have a big right-angle triangle -- 100' on the horizontal, 100' on the vertical, and a longer (about 141') diagonal. The Scheimpflug rule says that the tilt of the front lensboard to create that sloped focal plane will be achieved when the lensboard points to intersection (100' down) of the film plane and the focus plane. Since the lensboard is about 12.12" away from the film plane, it takes a mighty small angle to have it intersect at 100'. Like, about 0.6 degrees.
The closer the point of focus, the steeper the tilt of the front lensboard required to achieve 45 degrees focal plane slope (for two reasons: the vertical leg is that much shorter, and the lensboard is further away from the film plane). If the subject were 15' away, the lensboard tilt would be on the order of 4 degrees; at 8', 8 degrees.
That's the theory, as I understand it. Again, if I'm confused about this -- which is entirely possible -- I'd welcome correction. I'm just learnin' here ...
And your working distance in the studio is......?![]()
You have a better eye than I. I am certain I cannot reliably distinguish between a focal point 100 ft away and one 104 feet away using a 12" lens.
Photrio.com contains affiliate links to products. We may receive a commission for purchases made through these links. To read our full affiliate disclosure statement please click Here. |
PHOTRIO PARTNERS EQUALLY FUNDING OUR COMMUNITY: ![]() |