I contend there is no chemical test to distinguish one solution from the other if they are made with equally pure ingredients.
Both Sodium Bisulfite and Metabisulfite in solution (at 50g/L) are about 3.5-5 pH. The difference between them is that there is more bisulfite (or sulfite if you wish, but at that pH it is as the single protonated or hydrosulfite form, HSO3-).
The difference is that you get more sulfite/bisulfite with the metabisulfite per gram of material than with the bisufite.
And as you like to point out Pat, you probably can't point out the difference in solution, unless you happened to have an atomic absorption (AA)spectrophotometer or an inductively coupled plasma spectrophotometer (IPC) or any of the other methods of measuring the amount of sodium that is in solution.
Metabisulfite also goes by the archaic name of "pyrosulfite", which was used when a compound could be made into another compound through the act of intense heating. The heating drives off only water from an "ortho" acid or it's salt, like sulfuric acid forms pyrosulfuric acid (2H2SO4 - H2O => H2S2O7), pryophosphoric acid from phosphoric acid (2·HPO3 => P2O5*H2O), and of course, our topic of converstation, sodium metabisulfite from bisulfite (2·HNaO3S - H2O => Na2O5S2).
This is not water of hydration, which would also give a compound of higher "concentration" in the dry form, say like making a decahydrate salt into the anhydrous salt, but it also resulted in a different molecular formula, hence the new name for the new compound.
So metabisulfite is a distinctly different chemical with distinctly different properties and formula and molecular structure from bisulfite. The "pyro" form has more of the ortho acid anion than the original ortho acid form does.
But as Pat says, once they are put into water and are allowed to rehydrate, they are back to the original starting ortho acids or their corresponding anions.