May I suggest on the best method I have so far encounted to develop 35mm film?
If others can suggest a better method, I would like to learn about it.
That is absolutely not correct!
Yes Matt, I fully agree, but I still think my original post is the best method of developing a 35mm film.
Everyone thinks their way is the best way or they wouldn't be doing it that way
(I know of no minimum of Rodinal straight up necessary for each roll of 135 - 36 exp roll of film, but would like to if there is one.)
Rodinal
May I suggest on the best method I have so far encounted to develop 35mm film?
…
And never ever, ever after the film is fixed, washed and dryed, use a squeegee. Let the film dry naturally overnight in a bathroom or airing cabinet.
If others can suggest a better method, I would like to learn about it.
You should address your complaint to Kodak, not to me.
(1) Forgive me if I come out sounding pedantic here. I sincerely am not trying to be pedantic but I am pointing this out in the interest of accuracy.Pour 150ml of developer into a measuring jug and measure its temperature. If it is under or over 68F/20C, make a separate jug of water to compensate for the difference. Example if the developer temperature is 18C, make the water to 22C, before adding 150ml of developer.
(1) Forgive me if I come out sounding pedantic here. I sincerely am not trying to be pedantic but I am pointing this out in the interest of accuracy.
You are assuming that when mixing equal amount of 2 different liquids (water and stock D76) at different temperature would result in a solution having a final stable temperature equaling to the mean of the two temperatures — in your example, (18+22) ÷ 2 = 20.
But that is only true if (a) the 2 liquids have the same Heat Capacity, AND, (b) they are in a closed system (i.e., heat only exchanges between the two liquids). Even if we assume that the two liquids are in a closed system, I doubt that water would have the same Heat Capacity as the D76 stock solution. You can refer to this web page for the calculation of the final temperature: https://www.tec-science.com/thermodynamics/temperature/richmanns-law-of-final-temperature-of-mixtures-mixing-fluids/#:~:text=law of mixtures-,Adiabatic mixing,thermodynamic equilibrium will be reached.
(2) I have never been able to completely dissolve all the D76 powder at around room temperature, no matter how much I stir or shake the solution. Kodak recommend to mix D76 at around 125° F and that's what I do and use the developer when it cools down to around room temperature (changing time to match the actual temp.)
I understand your pedantic point, but perhaps I should of mentioned that after mixing the stock and water, I take the temperature of the 1:1 solution and if there is any variance from 20C (which usually there is not), I adjust the development time using my own time/temperature chart.
What is your own time/temperature chart, and how did you arrive at it?
(1) Forgive me if I come out sounding pedantic here. I sincerely am not trying to be pedantic but I am pointing this out in the interest of accuracy.
You are assuming that when mixing equal amount of 2 different liquids (water and stock D76) at different temperature would result in a solution having a final stable temperature equaling to the mean of the two temperatures — in your example, (18+22) ÷ 2 = 20.
But that is only true if (a) the 2 liquids have the same Heat Capacity, AND, (b) they are in a closed system (i.e., heat only exchanges between the two liquids). Even if we assume that the two liquids are in a closed system, I doubt that water would have the same Heat Capacity as the D76 stock solution. You can refer to this web page for the calculation of the final temperature: https://www.tec-science.com/thermodynamics/temperature/richmanns-law-of-final-temperature-of-mixtures-mixing-fluids/#:~:text=law of mixtures-,Adiabatic mixing,thermodynamic equilibrium will be reached.
In a nut shell, the correct calculation takes into account the different heat capacity of different substances. Heat capacity is "the amount of heat to be supplied to an object to produce a unit change in its temperature" (link to Wikipedia). In other words, the amount of heat energy released by substance A when its temperature is lowered by 1 degree isn't the same as the heat energy needed to raise the temperature of substance B by 1 degree if substance B has a different heat capacity. Therefore the final stable temperature wouldn't simply be the mean value of the 2 initial temperatures.I had a look at the link and both the formulas and the maths needed "blew my mind" but can I ask you and others who know a lot more than I what the difference will be between the example of (18+22) ÷ 2 =20 and what the formula in the link produces
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