WGibsonPhotography
Member
After reading Cus's pinhole camera thread, I decided that I wanted to build a pinhole camera (or at least design one on paper and give up after the math required to design one kicked my butt). 
I printed out an article on Geocities that gave the pinhole diameter formulas, f/stop formula (which I already knew), and other calculations. This article gives aperture diameter formulas in inches and millimeters. I decided to use millimeters because I'm more familiar with the metric system. The formula for pinhole diameter in millimeters is.
"Pinhole Diameter=0.0366(square root of focal length)"
Since I'm not a fan of math, I decided to use a nice, even number. I stupidly picked 1mm as my diameter, not thinking of how big that would make the camera. I ended up with a camera 15.8 feet long :\
If anyone is interested in how I (correctly ir incorrectly) came up with that, I'll type out my process.
Pinhole Diameter=0.0366(square root of focal length) with a 1mm pinhole diameter
1=0.0366(square root of x)
1^2=(0.0366^2)(x)
1=0.00133956x
1/0.00133956=x
x=746.5137806
I rounded 746.5137806 to 746.5mm
To get 15.8 feet, I multiplied 746.5 by 10 to get 74.65cm. I then divided 74.65 by 2.54 to get 29.38in.
This is actually a lot more practical than the calculation I had before. It's amazing how one mistake can throw a measuremoent off that much

I printed out an article on Geocities that gave the pinhole diameter formulas, f/stop formula (which I already knew), and other calculations. This article gives aperture diameter formulas in inches and millimeters. I decided to use millimeters because I'm more familiar with the metric system. The formula for pinhole diameter in millimeters is.
"Pinhole Diameter=0.0366(square root of focal length)"
Since I'm not a fan of math, I decided to use a nice, even number. I stupidly picked 1mm as my diameter, not thinking of how big that would make the camera. I ended up with a camera 15.8 feet long :\
If anyone is interested in how I (correctly ir incorrectly) came up with that, I'll type out my process.
Pinhole Diameter=0.0366(square root of focal length) with a 1mm pinhole diameter
1=0.0366(square root of x)
1^2=(0.0366^2)(x)
1=0.00133956x
1/0.00133956=x
x=746.5137806
I rounded 746.5137806 to 746.5mm
To get 15.8 feet, I multiplied 746.5 by 10 to get 74.65cm. I then divided 74.65 by 2.54 to get 29.38in.
This is actually a lot more practical than the calculation I had before. It's amazing how one mistake can throw a measuremoent off that much

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