As a rough estimate, a yellow is centered at about 450 nm, magenta at 550 nm, and cyan at 650 nm. Of course, this varies with product, unwanted absorptions and half band witdth.
But why do you have to ask me? You are an expert too! Aren't you?
You may want to look here: http://www.kodak.com/eknec/documents/bf/0900688a80316bbf/E7014e.pdf
for confirmation though.
PE
- - - if you are photographing a setting with thin fog, will the use of a blue filter accentuate the fog and increase its impact from foreground to background?
Quote:
Originally Posted by Ray Rogers
What happens to white light if you remove the green?
It appears coloured.
Look at page 4 of the reference I gave above at the Kodak web site, and see the spectral absorption of C/M and Y dyes with magenta at about 550 nm.
Magenta, being -G has maximum density at 550 nm on average and maximum transmission at wavelengths on each side. I understand what it says and how it acts alone and in combination with the other dyes. So, on a spectrum of density vs wavelength, you can assign magenta a wavelength, as you can with the other two subtractive dyes.
If you go here: http://en.wikipedia.org/wiki/Magenta you see it defined as a primary, particularly using the color wheel concept. It is defined as such elsewhere. Yellow however, has a dual definition: http://en.wikipedia.org/wiki/Yellow in which it can be defined as a primary or a mixed color due to the way humans perceive it. The latter reference cites work by Bob Hunt of Kodak BTW.
I also recommend "50 Years of the 1931 CIE Standard Observer for Colorimetry" by W. D Wright (Die Farbe 29 (1981), # 4/6, Page 2, fig 1 in which the CIE standard curve was designed essentially around a magenta centered at 550 nm!
PE
PE,
I'm really starting to believe that i am a better emulsion engineer than you are.
You are very tricky!
You know very well that removing the green content would reveal the presence of what you maintain is not there.
How many nm is magenta then?
That question has already been answered.
PE already said it is minus green and so did I when I gave you some approx. wavelengths....
It is clear that I cannot see your POV.
and as you admit, dropping the tricolor goggles does not help us photographically...
But you are correct!
There are different ways of looking at and producing color and vision and I don't doubt you are correct in at least one of those ways!
Unless it has some practical value in photography, however, I don't see why we would want to discuss it...
Anyhow, I will hand the floor over to you guys.
Try not tho hurt each other's feelings too much.
Just for the record... are you an emulsion engineer?
Ray
Red and blue? Yes. That's what we would be left with.
Excuse me...
You can see the Red and you can see the blue too, at the same time?
As unique colors?
I don't think so!
Not if you are human with normal vision anyway....
I think PE might have made a mistake, (550 nm max is probably absorption max... thus minus green, but even if I am right about that, it doesn't mean he doesn't know what he's trying to say.)
Remember that magenta is a subtractive color [...]
So....
PE
So?
So you are trying to save face by pretending we were talking about printing and CRT screens.
I'll not let you.
We were not.
None of that tri-colour (this must be the 100th time i wrote this) stuff is relevant. (And you did say things that were incorrect even if it would have been relevant).
The misquote of my post #46 is the source of this. I said that 550 is the absorption peak of magenta.
I stress this again.
PE
Tri color is relevant as it is the basis of all color photography (subtractive) and all video (additive). We cannot escape this fundamental fact!
Printing of color in magazines as an example, is relevant as they are using subtractive methods and dyes or pigments, and using a photographic original which is tricolor. This is all being viewed by a tricolor human eye!
In post #46, I said "A magenta can be represented by a dye or pigment with an absorption peak centered at about 550 nm. A yellow can be represented by a dye or pigment with an absorption peak centered at about 420 nm, and a cyan dye or pigment would have an absorption peak at about 690 nm."
In posts above you (QG and Ray) say [...]
This discussion exists because on an Analog Photography forum, I am trying to address color in terms of how a photographer and yes, a Photo Engineer would address it, not how a physicist or a neurologist would address it. Yes, I have had to do the matrix math and all of the other things necessary to compute color mixes, and yes, I follow what you are trying to say.
It does not fit well here and muddies the water when another approach is needed. That approach is tricolor. There is no other way to "solve" the problems. Even the matrix math is formed that way in most cases.
And, in the first iterations of the CIE and Munsell systems they didn't get it right. There were ammendments to the standard as knowledge evolved.
PE
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