I'm trying to mix up some of PE's superfix and sadly no longer can source ammonium hypo.
If I understand correctly mixing Sodium Hypo and Ammonium Chloride in solution in the following proportions should give me the 200ml of 60% ammonium hypo (plus a bit of salt):
128g of Sodium Hypo
87g of Ammonium Chloride
200ml of Water
Below are the balanced equations I used to arrive at this (bear with my HS chemistry).
Does this work? Or am I making a baseless assumption that all the hypo and chloride will react with each other?
Any tips on how to get the most out of this or is this just a plain dumb idea?
------------------------------------------------------Equation----------------------------------------------------------
1. Na2S_2O_3 + 2 NH_4Cl ⟶ (NH_4)_2S_2O_3 + 2 NaCl
2. 158g/mol + 2.53.49g/mol ⟶ 148.2g/mol + 2.58.44g/mol
3. 158g/mol + 106.98g/mol ⟶ 148.2g/mol + 116.88g/mol
This leads to a ratio of 1:1.066:0.721 Amm. Hypo : Sodium Hypo : Amm. Chloride.
So for 120g of Amm. Hypo we get: 120:127.92:86.52 which is roughly 120:128:87
If I understand correctly mixing Sodium Hypo and Ammonium Chloride in solution in the following proportions should give me the 200ml of 60% ammonium hypo (plus a bit of salt):
128g of Sodium Hypo
87g of Ammonium Chloride
200ml of Water
Below are the balanced equations I used to arrive at this (bear with my HS chemistry).
Does this work? Or am I making a baseless assumption that all the hypo and chloride will react with each other?
Any tips on how to get the most out of this or is this just a plain dumb idea?
------------------------------------------------------Equation----------------------------------------------------------
1. Na2S_2O_3 + 2 NH_4Cl ⟶ (NH_4)_2S_2O_3 + 2 NaCl
2. 158g/mol + 2.53.49g/mol ⟶ 148.2g/mol + 2.58.44g/mol
3. 158g/mol + 106.98g/mol ⟶ 148.2g/mol + 116.88g/mol
This leads to a ratio of 1:1.066:0.721 Amm. Hypo : Sodium Hypo : Amm. Chloride.
So for 120g of Amm. Hypo we get: 120:127.92:86.52 which is roughly 120:128:87
