Hello Robert,
I think you made a mistake there. First things first, so the atomic weights are: Na 23, C 12, O 16, H 1. So, that gives us Na2 (2x23) C (1x12) O3 (3x16) = 106 (molecular weight). So, 1 mol of Na2CO3 is 106g. The molecular weight of water is 18. Since the anhydrous form is 106g/mol, the monohydrate is 106+18=124g. The decahydrate would be 106+(10x18)=286g.
Anhydrous -> Monohydrated: 124/106=1,17 multiplication factor
Anhydrous -> Decahydrated: 286/106=2,69 multiplication factor
Monohydrated -> Anhydrous 106/124=0,85 multiplication factor
Decahydrated -> Anhydrous 106/286=0,37 multiplication factor