Chan Tran
Subscriber
For a lens of focal length f, and an extension past infinity of e, the magnification M is given by:
M = e / f
The distance of lens to image is: d_i = f + e.
These formulae agree with the ones given earlier in the thread if you do some algebra to rearrange them.
The difficulty with using the formula exactly is that the distance of lens to image is really the distance from rear principal point to the image, not the flange distance or the distance of the aperture from the image. But this is usually only a few mm off.
From this we can see that with your setup of a 50mm lens plus minimum 35mm extension past infinity, it would give a minimum magnification of 35/50 = 0.7x, which is a bit more than you wanted, so the 50mm enlarging lens plus bellows wouldn't be a good choice for duping 35mm onto APS-C.
In general, 50mm lenses don't provide a lot of working distance at magnifications near 1:4 to 1:1. If you want to do that, choices include: getting an SLR macro lens with a normal focus ring and some extension tubes; or using a longer f.l. enlarging lens on a bellows or similar; or buying a focusing helical mount and then messing around with a bunch of different adapters to get the extension within the travel of the focusing helical.
The op need a magnification of 1:7.6 which is in most macro lens range without any extension. The negative that the OP want to digitize is quite large 13x18cm.