Well, I've made some (unscientific) test scans of dense and thin materials, with and without adjustments. I've timed each scan,
...
For what it's worth, I was scanning with Silverfast at 16-bit colour positive (colour negative materials).
are you saying scan flat (meaning the curve) with the scanner software in negative mode?I can scan flat and make the same kind of change in PP using PS Elements.
The scanner software is doing the same thing after the scan except it seems like it's changing it during the scan.
as I said initially, you're thinking like this is a digital camera. This is scanning a negative, unlike a scene this is actually all there is to it.But it isn't as far as I can tell. How could it other than by changing speeds. Then you would have to do two scans (something that Silverfast does if set to do). Then combine afterward like HDR.
as far as I know the only way to do that is to tweak your photomultiplier which is what drum scanners do. So from the absolute theoretical standpoint (and ignoring all the reality inbetween) yes, your right.The one area where I can agree the scanner may make a change is if by moving the black and white points, the data file will have more data of actual exposed light on the film than if you captures the light 0-255 from the whole film.
For example, if the range of a particular picture was 20-230 and you moved the points in so the full capture was from 20-230 rather than 0-255, than it is possible that you'd have more data to work from. Of course, the physical scan is the same either way. But the post processing by the scanner program provide more data about the actual light that makes the picture. Does anyone know if this actually happens?
ok, but first can you clarify how much maths you understand? Do you understand the difference between floating point maths and integer maths?Can you clarify your last paragraph? The first sentence says thats you do not get "a better range data" by altering the scan. The second says "unsquishing the curve" is "significant". If you don't get "a better range data", how can "unsquishing the curve" be "significant"?
Results: Scan 2 with auto giving 5-255 was very slightly smaller than the scanner output file in Scan 1. There's only 37,000 pixels or .01 percent difference. That could be because the ICE was turned on in Scan 2. Regardless, that's an insignificant amount a data and it's less data in Scan 2 with adjustments than in Scan 1 without adjustments. Moving the white point before the scan from 255 to 185 using Auto scan adjustments gave no additional data.
THERE ARE NO DIFFERENCES IN QUANTITY OF CAPTURED DATA BETWEEN SCAN 1 AND SCAN 2 REGARDLESS IF YOU SET BLACK AND WHITE POINTS DURING SCAN OR NOT.
Pellicle, it seems to me your explanation is less relevant for 16-bit data.
But my Histograms look the same whether I set black and white points in the scanner or in Elements. So explain to me why it should be different and how.
Chuck: Thanks for your thoughts. I've compared both my scans where one scan was scanned flat and was post processing in Auto Levels in PSE-8. It matched the image results in Auto set before the scan. So that test didn't seem to prove that one way is superior to the other. However, I might be fooled because I'm depending on my eyes in a small image on a computer screen.
Here are questions I asked previously but didn't get responses. Maybe you can answer them. I'm trying to understand how the scanner creates its image scan file. That may answer the question of which way is better.
1. If I have a film that has a histogram range of 0-165, will I get more data in the scan file to work on if I move the white point in the scanner from 255 to 165 rather than leaving it "flat" and scanning the full 0-255? In other words, will the data file at the end of the scan have more data representing the 0-165 then the same 0-165 area if I scanned "flat" from 0-255?
2. How could I measure the difference between moving it and scanning "flat" assuming pixel count and file size does not provide that information as someone stated above?
Thanks. Alan
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