I would imagine Ralph has used it.
I think I was wrong about the HC-110 being overactive. I now think it is just about right.
I graphed this on paper and overlaid a transparent Contrast Index meter.
It was difficult to find the Base + Fog point to zero the meter, so I fudged by moving it up.
When I fudged the zero, I came out with CI's:
4 Min > CI 0.4
5.5 Min > CI 0.45
8 Min > CI 0.5
11 Min > CI 0.6
16 Min > CI 0.7
For a 1.0 LER, this set came very close to being:
4 Min > N-2
5.5 Min > N-1
8 Min > N
11 Min > N+1
16 Min > N+2
When input my CI as average gradients in blue cells of Ralph's spreadsheet:
4 Min > N-3
5.5 Min > N-2
8 Min > N-1
11 Min > N
16 Min > N+1
Summary:
1) You expected and got very clear N-2 to N+2.
2) The data points are hard to fit to curves.
In 4 min HC-110 (1+63 AKA Dilution H) your raw data shows you get 1.0 NDR over 8 stops.
That's "N-1" the way I work.
It is not a huge difference that the spreadsheet calls this "N-0.4" (If I read the formula correctly Ralph uses the constants 1.2 NDR over 7 stops to define "N").
Relatively speaking, I think you are getting more development activity than you might want... since you got a lot of density in 4 minutes.
If development results are even, then there you have it: You have a rapid process. If you are getting uneven results, then you might pick XTOL for any film you mark for "N-1" or less development.
p.s. I work for Kodak but the opinions and positions I take are my own and not necessarily those of EKC.
As per Ralph, the density readings for the "Input Data" tab are to be input as total density, so they include b+f
...
I have input "net" densities into the spread sheet and ... at the "curve family" tab, one would see "net" density data indicated by a "level" red line at Dmin across all curves. This is opposed to a red line that would be slanted across all curves....
I've made a simple Time / Gradient graph in Excel using the data from Chuck's spreadsheet. While the rate of development isn't very steep, except for the 8 minute test, there doesn't appear to be a problem with the overall progression.
Chuck,
If Ralph's spreadsheet calculates gradient in the way he describes in his book, it's base point is higher on the curve than what is normally used. Placing the base point higher on the curve will mostly factor in the straight-line portion of the curve and produce a higher gradient value than if the reading incorporated more of the toe. The two shorter timed tests of yours show a bit of a toe. There's a good chance this is the reason for higher than expected gradients. Like Bill indicated, if you measure the curves using different methodology like CI or average gradient with a 0.10 base point, you will get different results. I believe you might find them to be closer to what you are expecting.
Also, I tooled around with the charts, just to add things graphically that help me when evaluating them, but that's just me.
Hope you don't mind but I'm attaching a version in Open Document Format for those who haven't paid Microsoft to use spreadsheets. Let me know if you want it deleted.
Lee
Not much difference there.....the off set is due to the sheet's formulas being set up for a NDR of 1.2, your suggestion was an NDR of 1.1. Maybe Ralph will chime in on it soon.
That's interesting. Thanks for taking the time to do that. I decided to plug your numbers into my program. I got values very close to those Bill got with his hand drawn curves and CI overlay.
Results from my program:
4 min 0.41
5.5 min 0.44
8 min 0.50
11 min 0.57
16 min 0.68
My program uses a variation of contrast index where it uses 0.10 as a base and draws an arc 2.0 log-H units to the right. As described in Photographic Materials and Processes. Just to help illustrate the how the various methods of measurement can effect the results, my program also does Ilford's G bar with a log-H range of 1.50 and an average gradient with a log-H of 1.80. I got 0.72 for the 1.80 average gradient method.
And here's a Time/CI Graph. As you can see, it's smoother than the one derived from the values from Ralph's spreadsheet, which is a positive indication as to the validity of the results.
View attachment 52570
We use cookies and similar technologies for the following purposes:
Do you accept cookies and these technologies?
We use cookies and similar technologies for the following purposes:
Do you accept cookies and these technologies?