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I received from Rudeofus (thanks) a Kodak paper "The autoxidation of phenidone", W E Lee & Eva Zahorian, Photo Sci Eng 12 no5 1968 p251-262,
In most developers except those like POTA the phenidone gets regenerated by a secondary agent and the work described does not apply, and in stock solutions of phenidone in (say) 70% isopropanol the pH is about 6 which is below the range of pH 7.8 to 9.2 considered in the paper. So I just summarize a few points from this paper, [with comments by me in brackets].
The authors elucidated the mechanism of oxidation of phenidone by oxygen in the pH range 7.8-9.2.
Phenidone is first ionized and the phenidone anion reacts with O2 to give the semiquinone and the HOO. radical.
The semiquinone then disproportionates giving phenidone and 1-phenyl-3-hydroxy-pyrazole [this latter is the usual oxidation product of phenidone and is the ionized form of pyrazolone mentioned in Mason's book Photographic Processing Chemistry]
[IIRC the oxidation of ascorbate proceeds in a similar way]
The HOO. radical probably forms hydrogen peroxide and O2.
Hydrogen peroxide reacts with phenidone giving colored oxidation products.
If sulfite is present [as in POTA] it probably mops up hydrogen peroxide and slows down this previous reaction.[This is presumably the way in which sulfite acts as preservative for phenidone in POTA].
Copper (II) and Iron (III) catalyse the oxidation, they may form complexes with phenidone which can bind molecular oxygen more easily than phenidone. [May again be like ascorbate].
In most developers except those like POTA the phenidone gets regenerated by a secondary agent and the work described does not apply, and in stock solutions of phenidone in (say) 70% isopropanol the pH is about 6 which is below the range of pH 7.8 to 9.2 considered in the paper. So I just summarize a few points from this paper, [with comments by me in brackets].
The authors elucidated the mechanism of oxidation of phenidone by oxygen in the pH range 7.8-9.2.
Phenidone is first ionized and the phenidone anion reacts with O2 to give the semiquinone and the HOO. radical.
The semiquinone then disproportionates giving phenidone and 1-phenyl-3-hydroxy-pyrazole [this latter is the usual oxidation product of phenidone and is the ionized form of pyrazolone mentioned in Mason's book Photographic Processing Chemistry]
[IIRC the oxidation of ascorbate proceeds in a similar way]
The HOO. radical probably forms hydrogen peroxide and O2.
Hydrogen peroxide reacts with phenidone giving colored oxidation products.
If sulfite is present [as in POTA] it probably mops up hydrogen peroxide and slows down this previous reaction.[This is presumably the way in which sulfite acts as preservative for phenidone in POTA].
Copper (II) and Iron (III) catalyse the oxidation, they may form complexes with phenidone which can bind molecular oxygen more easily than phenidone. [May again be like ascorbate].

