River Mantis
Member
From Haist, p. 447
So the weight ratio of Metol would be
X = K*r/(K*(r-1)+1) ~ 0.55
where
K = 0.28
r = MMetol/MHQ = 344.38/110.11
So the developer should have slightly more Metol by mass than HQ but in most formulas we have 3-6 times more HQ than Metol by mass. What am I missing?
There is also an old post where a graph from LFA Mason's book was posted showing the maximum rate at about 25-30%. The graph is labeled "Effect of the molar ratio of Metol to hydroquinone on developer activity" which is probably misleading. Just from the graph itself and the notion of the total concentration in centimoles per litre I assume that this is indeed a ratio of Metol to total quantity of two compounds.These authors [A. J. Axford and J. D. Kendall] found that the maximum rate of development for an MQ series of developers was obtained when the molar percentage of Metol was 28 %
So the weight ratio of Metol would be
X = K*r/(K*(r-1)+1) ~ 0.55
where
K = 0.28
r = MMetol/MHQ = 344.38/110.11
So the developer should have slightly more Metol by mass than HQ but in most formulas we have 3-6 times more HQ than Metol by mass. What am I missing?