In order to measuer the voltage transform adapter using a digital tester, put a 10Kohm resistance between the measurement terminals.
Reduction from what?But I cannot see such voltage reduction.
Thanks, I should have taken a look at some diode datasheets from the startSchottky diodes (like most/all diodes) have a forward voltage drop that depends on the current through the diode. It usually rises weakly with current at small currents and then changes more steeply at currents that are much larger than anything an MR9 adapter would ever see. For example, here's a plot from the datasheet for a BAT54 Schottky diode, I've rotated it so forward voltage is on the Y-axis. You can see that the Vdrop is about 0.15 V at 0.01 mA and 0.25 V at 1 mA. When you hook a digital voltmeter up to it, which probably has an input resistance of hundreds of Kohms or more, you're measuring with a current draw of a few micro-amps or even nano-amps.
Probably, the designer of the MR9 picked a diode that drops about 0.2 V under a typical current draw of perhaps a few milli-amps. Understand that most older light meter circuits are pretty simple, often using a few resistors and a light-sensitive element to approximate logarithmic sensitivity, not a precision laboratory instrument. Bottom line, most users are happy with the adapter.
Look at the first picture, where I am taking a reading of the battery without the adaptor.Reduction from what?
I don't see that you measured the voltage of the battery by itself without the adapter so how would you know what the reduction is?
If you used an LR44, they are often about 1.6v or even a bit higher when new. So, a reduction from 1.6v to 1.4v would be about right.
But, you shouldn't use LR44 or any alkaline battery with these adapters because their voltage drops continually in use.
Use a silver oxide S76 type. Their voltage curve is much flatter.
And, I would measure with a better quality meter like a Fluke for example. When you're trying to measure tenths of a volt you need an accurate meter.
Look at the first picture, where I am taking a reading of the battery without the adaptor.
Huh? I mean, a battery will give vastly different voltage readings based on load and its chemistry, so normally they're measured open circuit.Yes, but not with the resistor. Direct readings of batteries without a load resistor are not accurate
Yes, but not with the resistor. Direct readings of batteries without a load resistor are not accurate
But, the second picture shows you measuring WITH the MR-9! Obviously, you don't get what I'm saying.That is the second picture.
But, the second picture shows you measuring WITH the MR-9!
I consulted a resistor catalog and found that resistors of 1.7KΩ are available. Even a 2KΩ resistor might give a more meaningful result.
You mean he should measure the battery with just the 10kOhm load, then measure it with the 10kOhm load and the MR-9 adapter, and compare the difference, right?
I use it in my OM-1n for years now. It's clear to me: plain silver button battery shows values different than when it's in its adapter, so it works. And my exposures are stable, so it works.
And I wish all well in their electrical measurement adventures!
We use cookies and similar technologies for the following purposes:
Do you accept cookies and these technologies?
We use cookies and similar technologies for the following purposes:
Do you accept cookies and these technologies?