jay moussy
Member
Use advice to someone new (and in need of shopping for) a 28mm lens?
Use advice to someone new (and in need of shopping for) a 28mm lens?
I enjoy the 24 - 35 focal range. I have a 24mm Nikon that I use on my full frame and aps-c camera which gives me a 24 on the FF and 36 equivalent focal range on the aps-c. I enjoy both focal ranges. I have a 15mm that I rarely use but it works on rare occasions.
Very wide angles lenses such as 15m to 20mm are limited in practical use. Newbies use them to take in the whole scene and loose all the details and that is not a good use for those lenses. Those lenses generally do well for one object close in getting all the attention and the rest just falls into place.
Sometimes that's true. Other times not so much.
What is the 35mm equivalent of the 38mm lens on your Hasselblad SWC? There are a couple of different ways of doing the conversion, but I think it is around 21mm. I thought you were pretty high on your SWC. Is it really of limited practical use?
What formula did you use for your conversions?
To avoid having to use trigonometry, here is a link to a page on Histrorical Hasselblad which gives lens equivalents calculated on 1) horizontal angle of view, 2) vertical angle of view, and 3) diagonal angle of view:
Hasselblad Historical - Focal length comparisons
www.hasselbladhistorical.eu
Images from the 38mm lens on the SWC look wider to me than a 24mm lens on a 35mm camera.
I am using an approximation because I can do the calculation in my head. To accurately calculate the comparison would require memorizing the complete trig tables, and I frankly do not have time for that.
Trig tables? Aren't we really just talking about the using the Pythagorean theorem. Common Core calls for the Pythagorean theorem to be taught in the 8th grade. Or if that is too complicated, you can just look it up on the chart I linked to. Surely you have memorized the conversions for the lenses you have by now so you don't have to do the calculations each time you use a lens?
Excuse me, but what?! Phytagirean theorem, trig tables? You need nothing but a factor, which is the ratio of the dimension your interested in, say the widths, of both formats you're comparing. Ok, Pythagorean theorem does come in if you're interested in diagonals.
Crop factors are determined by the diagonal. I think that is the way to go. Otherwise, there is a wide difference when you compare lenses between formats using height vs. width calculations, neither of which look quite right.
But using the diagonal means nothing when comparing 6x6 with 24x36. The diagonals just do not convey the different formats.
And width and height do?
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