+1EV is a measure of exposure - f-stop & shutter speed - not light intensity. So those values are at a reference film speed of ASA100.
The 14,400 number that you are sharing is close to correct for converting EV to Lux. Lux = 2.5 * (2^EV), so the actual number is 14,481.5 Lux.
To calculate milliLux, multiply by 1000.
EV is a measure of exposure - f-stop & shutter speed - not light intensity. So those values are at a reference film speed of ASA100.
Are you using f/1.0 for 1/5000 second?
So.......14,481,500.5 milliLux,
Then multiplying by .25 sec = 3,620,375.125 milliLux-seconds. Am I getting this part right?
Then taking the Log 10 (3,620,375.125) = 6.56 log exposure? Am I getting the conversion to log exposure correct? If so that's way out there on the x-axis.
So.......14,481,500.5 milliLux,
Then multiplying by .25 sec = 3,620,375.125 milliLux-seconds. Am I getting this part right?
Then taking the Log 10 (3,620,375.125) = 6.56 log exposure? Am I getting the conversion to log exposure correct? If so that's way out there on the x-axis.
lux = (2 ^ EV100) * 2.5
EVS = EV100 + log2(S / 100)
If that question is to me.........no.
Yes, what that is telling you is that a 1/4 second exposure for ISO 100 film would be way overexposed, i.e. above the shoulder of the characteristic curve. If you are doing sensitometry to measure the response of some test film, you want to either reduce your exposure time or illuminance to get good measurements across the characteristic curve.
Yes, that makes sense to me now because I exposed a step tablet contacted to my film in the holder. I placed EV12 and 2/3 on Zone X (Schafer's film test method). The exposure was 1/4 sec at f/5.6 and 2/3. The overexposure was intentional to comply with that method. I got curious as to how my spot meter's EV number translates to millilux-seconds.
But EV12 2/3 was a measure of incident light
I don't understand this...............12 2/3 was a measure of the reflected light off the test target.
It was the meter’s evaluation of what the incident light is.
If you had used an incident meter, it would have used a corresponding set of assumptions to arrive at the same EV.
Anyway the graph paper shows you how much light you put on the film, I worked back from what the meter was trying to do.
Now to answer “What was the meter trying to do?”…
Stephen has done presentations on it. Look for one of his threads like “What is K”.
I'm hearing that my Pentax 1 degree spot meter is actually providing me with an incident reading.....another thing I'm going to have to try and wrap my head around. So there is light that is incident upon the target but the light entering the spot meter is reflected from the target. Is this an incorrect statement?. But still the light meter was estimating the incident light according to what it wants to put on film.
The EV to Lux calculator I referenced earlier said that my 12 2/3 EV (that I placed on Zone X) was 14,400 Lux. So I wondered....... to get millilux, I multiplied by 1000? Then multiply millilux by the exposure time, which was 1/4 sec to get millilux seconds, which was 3,600,000? Then the log 10 (3,600,000) is 6.5? Then I said that's way out there on the x-axis........then someone said that's because I way over exposed. Well, I did, I did way over expose, by 5 stops, on purpose.......and so here we are.I am sure interested in what took you down from 3,620,375.125 millilux seconds (your reading) to 2512 millilux seconds (my estimate).
I asked if I had those calculations wrong, don't believe anyone said no......I'm not saying it's right, I put it out there to ask if it was, so idk.
I'm hearing that my Pentax 1 degree spot meter is actually providing me with an incident reading.....another thing I'm going to have to try and wrap my head around. So there is light that is incident upon the target but the light entering the spot meter is reflected from the target. Is this an incorrect statement?
The EV to Lux calculator I referenced earlier said that my 12 2/3 EV (that I placed on Zone X) was 14,400 Lux. So I wondered....... to get millilux, I multiplied by 1000? Then multiply millilux by the exposure time, which was 1/4 sec to get millilux seconds, which was 3,600,000? Then the log 10 (3,600,000) is 6.5? Then I said that's way out there on the x-axis........then someone said that's because I way over exposed. Well, I did, I did way over expose, by 5 stops, on purpose.......and so here we are.
I asked if I had those calculations wrong, don't believe anyone said no......I'm not saying it's right, I put it out there to ask if it was, so idk.
The Pentax spot meter is a reflectance meter, not an incident meter.
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