A front-focusing 50mm f/1.5

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loccdor

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I want to get more use out of my Jupiter-3 50mm f/1.5 lens. I know the ideal is to get it shimmed by a professional, let's leave that aside for a moment.

What I learned about it so far:

1) The lens at f/1.5 front-focuses by approximately 5 cm at the minimum focus distance of 0.9 m with the Kiev 4 rangefinder.
2) The lens at approximately f/4-f/5.6 is focusing accurately (focus shift).
3) I mostly only want to use this lens wide open, for its character. I have a Jupiter-8 when I need a more technically perfect shot, which has no focusing issues.
4) Each f-stop down shifts the focus at the MFD away by approximately 1.5 cm.

The markings for a 5 cm focus shift align with the DoF scale mark at f/4.

IMG_9598.jpg
IMG_9599.jpg


I'm thinking I'll focus in the rangefinder, look down at the lens and focus out until the f/4 mark. Then things should be accurate for a wide open shot. Kind of like how you'd adjust for the infrared mark.

IMG_9600.jpg
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That would imply, by these pictures, that when the camera is focused on infinity wide open, it's actually at 15 meters.

Does all this seem to be sound logic?
 

brbo

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Yes, you can learn how to "focus out" on the lens or perform "chicken head" move. I do the latter with my Sonnar that is optimized for f2.8-f4.
 

Rumbo181

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Just an idea.

I have a number of Soviet lenses with LTM mount. When I use one of them on a Leica and focus with the rangefinder on a target at 2 m, I might read 1.8 m on the lens scale — just as an example. If I repeated the process at different distances, I could get a correction curve for the lens. Actually the error is always predictable.

For instance, imagine that at short distances you get a −10 % error. Then:
  1. Focus using the rangefinder.
  2. Read the distance indicated on the lens.
  3. Refocus the lens to the previous reading +10 %.
This way you can still use the camera’s rangefinder without making any physical modification to the lens.
 
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loccdor

loccdor

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If I repeated the process at different distances, I could get a correction curve for the lens.

Thanks. Since the distance markings on the lens are already on a "curve", wouldn't determining a constant offset mark (as exists on infrared lenses) be the same as adding a % to the distance?

how did you determine the 5 cm focus "shift" at minimum distance ?

Test shot wide open at minimum focus distance. The lens focused on something approximately 5 cm closer. My other lenses with this rangefinder focus well.
 

Rumbo181

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Thanks. Since the distance markings on the lens are already on a "curve", wouldn't determining a constant offset mark (as exists on infrared lenses) be the same as adding a % to the distance?

Actually, I should thank you for your post.

At first reading, I took for granted that focus shift was just a generic way of referring to a mismatch between rangefinder and lens information.

Then I read it more carefully and realized that “focus shift” is actually the name of a known and documented effect that happens with some fast lenses at wide apertures, shifting the focus as you stop them down. I certainly didn’t know that — so, thank you.

Furthermore, I realized that I should read more carefully. This is not a language problem, but rather a too-much-Internet problem. Thank you again.

What I proposed was the centuries-old method of recording the difference between an observed measurement and the real one, keeping that difference in a table so it can be used to find the true value from the observed one. If I understood your initial post correctly, this is essentially what you did.

I used a constant difference — a percentage — just as a way to illustrate the method, that’s all.

And now, two considerations:

I suppose that focus shift depends on the difference in f-stops (which could be fixed, let’s say from f/1.5 to f/8), but it’s not certain that it has a fixed relationship with the lens–subject distance. I believe it diminishes with distance.

Actually, I did the classic thing: I asked AI, and it brought back this little table:

Cause Type of change Δv in image plane Δu in object space Fixed mark valid?
🔴 Infrared light Difference in wavelength (constant for λ≈800 nm) Constant Variable but proportional ✅ Yes
⚪ Focus shift Spherical aberration (dependent on distance and aperture) Approximately constant, but varies with u Tends to 0 at infinity ❌ No
Δv is the variation in the image plane (the negative), and Δu is the variation of focus in the lens–subject distance.

To summarize: a fixed mark is not really valid (hence the oddity of your last two pictures), and the effect of focus shift becomes less worrying as the distance increases. I suppose that at around 5 m it would be hardly noticeable — though of course, it’s always possible to do a test to find the distance at which the effect can be safely ignored.

I hope this helps.

By the way, I have two Kievs with their Jupiter 8. Is Jupiter 3 a good complement?
 
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