Thanks. Since the distance markings on the lens are already on a "curve", wouldn't determining a constant offset mark (as exists on infrared lenses) be the same as adding a % to the distance?
Actually, I should thank you for your post.
At first reading, I took for granted that
focus shift was just a generic way of referring to a mismatch between rangefinder and lens information.
Then I read it more carefully and realized that “focus shift” is actually the name of a known and documented effect that happens with some fast lenses at wide apertures, shifting the focus as you stop them down. I certainly didn’t know that — so, thank you.
Furthermore, I realized that I should read more carefully. This is not a language problem, but rather a too-much-Internet problem. Thank you again.
What I proposed was the centuries-old method of recording the difference between an observed measurement and the real one, keeping that difference in a table so it can be used to find the true value from the observed one. If I understood your initial post correctly, this is essentially what you did.
I used a constant difference — a percentage — just as a way to illustrate the method, that’s all.
And now, two considerations:
I suppose that
focus shift depends on the difference in f-stops (which could be fixed, let’s say from f/1.5 to f/8), but it’s not certain that it has a fixed relationship with the lens–subject distance. I believe it diminishes with distance.
Actually, I did the classic thing: I asked AI, and it brought back this little table:
Infrared light |
Difference in wavelength (constant for λ≈800 nm) |
Constant |
Variable but proportional |
Yes |
Focus shift |
Spherical aberration (dependent on distance and aperture) |
Approximately constant, but varies with u |
Tends to 0 at infinity |
No |
Δv is the variation in the image plane (the negative), and Δu is the variation of focus in the lens–subject distance.
To summarize: a fixed mark is not really valid (hence the oddity of your last two pictures), and the effect of
focus shift becomes less worrying as the distance increases. I suppose that at around 5 m it would be hardly noticeable — though of course, it’s always possible to do a test to find the distance at which the effect can be safely ignored.
I hope this helps.
By the way, I have two Kievs with their Jupiter 8. Is Jupiter 3 a good complement?