Diffraction increases as the pinhole gets smaller, which means that if you go smaller than the optimum size, you will get a softer image as well as longer exposure.
The optimum is the optimum because it is the point with greatest sharpness - too small and you're diffraction-limited, too large and you're limited by the tube of light coming through the hole.
To further complicate the discussion, in a flat film camera, a pinhole of optimum size for the center of the image is too small for the corners of the image. Also, the corners exhibit astigmatism. For the curved film "Oatmeal box" camera, the pinhole can be made slightly elliptical to improve edge performance. Even something as simple as a pinhole camera can become awfully complicated.
Seen from under an angle, not from straight behind, a circle appears as an ellips, is smaller.
Make the hole ellips shape, and from the side the long axis points to, the effect is negated. But only from that side, and only at a certain angle/distance from the image's centre.
I don't know how that would creat astigmatisme, except that the shape is echoed in the pencil of light's shape. But that's not astigmatism.
Seen from under an angle, not from straight behind, a circle appears as an ellips, is smaller.
Make the hole ellips shape, and from the side the long axis points to, the effect is negated. But only from that side, and only at a certain angle/distance from the image's centre.
I don't know how that would creat astigmatisme, except that the shape is echoed in the pencil of light's shape. But that's not astigmatism.
My non-mathematical understanding is that 'optimum' is that, because, if the hole is larger, then excess unfocused or incoherent light rays are allowed and begin to blur the image; and if the hole is smaller, diffraction begins to blur the image.
So the optimum hole size is the least blurry point between those 2 causes of blurriness.
Does that sound accurate to others?
I have a pinhole that works wonderful on a home made pinhole camera that takes a 4x5 negative. Why couldn't I transfer this pinhole to another camera with a longer focal length.
What function describes the image's circle of confusion from the diffraction and the CoC from just the hole?
MB
Nick Kanellos said:What function describes the image's circle of confusion from the diffraction and the CoC from just the hole?
MB
d=1.56√λf
where
d = the pinhole diameter
λ = the wave length (about 0.000555mm)
f = the focal length
Taken from "Way Beyond Monochrome. 2nd ed." p. 155
You can. So long as you don't mind slight increase in image fuzziness and a significant increase in exposure times.
Two things make the image on a pinhole camera fuzzy: the size of the pinhole, and the effects of diffraction, the bending of light around an edge. But only the light that 'touches' the circumference of the pinhole will be diffracted. In both cases (i.e. short camera, long camera), the same amount of light is being diffracted (i.e. bent slightly outward radially). That bent light will spread out as it heads toward the film, increasing the overall fuzziness of the image. On a longer camera, it has a longer path in which it can spread out before it hits the film. So you may find that your images will be less sharp on the longer focal length camera, even with the same pinhole. And, you'll still have to pay the price of longer exposure times.
So, you could make yourself a bigger pinhole and shorten your exposure times. True, you'll increase the fuzziness due to the size of the pinhole. But you'll decrease the fuzziness due to diffraction. However the net fuzziness will probably be higher.
And if you really want to get technical, even in the bigger pinhole, the total amount of light being diffracted (i.e. bent or scattered) will increase, but the proportion will be less. And so it's relative contribution to image fuzziness will be less.
Easy, eh?
Beyond focal length and the physical size of the pinhole, I can think of several more aspects that when considered in the pinhole's design will most likely increase the sharpness (reduce defraction) in the projected image.
1. The shape of the pinhole.
2. The thickness of the pinhole plate material (at the pinhole)
3. The color of the pinhole plate material (at the pinhole)
Would someone care to elaborate further?
Is this the Formula for an optimum size?
Let me take a stab:
1) The shape of the pinhole. I suppose you could say that the amount of light diffracted is proportional to the perimeter of the pinhole. The smallest perimeter for any given area (e.g. the area of the pinhole itself) is a perfect circle. Anything else adds more 'edge' around which more light can be diffracted. Which results in reducing sharpness. How'd I do?
2) Thickness of the plate material. Let's see. Hmmm.... Imagine light coming into the pinhole at any angle from the axis. Some of that light will "touch" the front edge of the pinhole. Resulting in some diffraction. Some of the light will then "touch" the rear edge of the pinhole. More diffraction. Any thickness greater than zero effectively results in "two" pinholes: one at the front surface of the plate and one at the rear surface. Effectively doubling the diffraction causing edge. Also a thicker plate effectively reduces the pinhole aperture for any light not coming straight from the front.
To remedy this, once you've drilled your pinhole, take a counter sinking drill bit and create a conical shaped hole over your pinhole. If you get it just right, it will result in a near knife edge perimeter for your pinhole. It might make it a bit delicate but no more so than a glass lens.
3) Colour. Not a clue.
Beyond focal length and the physical size of the pinhole, I can think of several more aspects that when considered in the pinhole's design will most likely increase the sharpness (reduce defraction) in the projected image.
1. The shape of the pinhole.
2. The thickness of the pinhole plate material (at the pinhole)
3. The color of the pinhole plate material (at the pinhole)
Would someone care to elaborate further?
d=1.56√λf
where
d = the pinhole diameter
λ = the wave length (about 0.000555mm)
f = the focal length
Taken from "Way Beyond Monochrome. 2nd ed." p. 155
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