Hello everyone,
something has been bugging my mind for months now in regards to dense negatives and scanning.
Generally I tend to the dense negative side when it comes to shooting black and white (and also C41, actually) film, believing that the film contains more tonal differentiation especially in the shadows and is easier to print in the darkroom, and considering that film is definitely more forgiving to overexposure than underexposure.
When it comes to scanning these dense negatives, what I was wondering is the following: I am sure scanners have some kind of dynamic range in which they can capture tones. It would seem to me that if the negative is very dense you have all the tones on the dark end of the scanner's dynamic range – which makes me wonder if the scanner would be able to capture all these tonal differences, especially considering that it can theoretically capture more tonal differences on the highlight end of its dynamic range due to the nature of digital sensors (keyword "exposing to the right" – see https://en.wikipedia.org/wiki/Exposing_to_the_right for technical background)
As an example, when I scan negatives with Hasselblad's/Imacon's Flextight scanner, I get a histogram in the preview scan of the negative that shows the scanner's dynamic range and the tones of the negative fall somewhere inbetween. For very thin negatives the histogram is shifted towards the right/bright side, for very dense negatives it is shifted to the left/dark side (as it should be), without ever clipping or touching the borders (the scanner's dynamic range is larger than the tonal range that can be on the negative). Considering the nature of digital sensors, it would seem like the scanner would catch most tonal information if the histogram of the negative is spread out over as wide the dynamic range of the scanner as possible, or if it peaks towards the bright side of the histogram. A very dense negative's tones are spread out over only a very small part of the scanner's dynamic range/histogram, which on top of that is the dark part that contains less tonal separation - which seems like a bad idea.
There's probably some flaw in my way of thinking and it is driving me crazy that I can't wrap my head around it! – maybe you know where I am wrong? Is a dense negative bad for scanning?
P.S: Bonus question to those who know more about the workings of the Flextight/Imacon scanner in particular (could not find an answer in their manual): Does it make a qualitative difference if I scan a negative using the whole dynamic range the scanner provides me (setting white and black point to 0 and 255 during scanning, respectively) and then setting the white and black point I actually want for my image in post-processing, compared to setting that white/black point BEFORE scanning in the scanner software?
It seems to me that all that setting the white and black point before scanning does is, technically, making the scanner scan at full dynamic range anyway and then clipping/remapping the tones according to my settings in post - so basically the same as above.
something has been bugging my mind for months now in regards to dense negatives and scanning.
Generally I tend to the dense negative side when it comes to shooting black and white (and also C41, actually) film, believing that the film contains more tonal differentiation especially in the shadows and is easier to print in the darkroom, and considering that film is definitely more forgiving to overexposure than underexposure.
When it comes to scanning these dense negatives, what I was wondering is the following: I am sure scanners have some kind of dynamic range in which they can capture tones. It would seem to me that if the negative is very dense you have all the tones on the dark end of the scanner's dynamic range – which makes me wonder if the scanner would be able to capture all these tonal differences, especially considering that it can theoretically capture more tonal differences on the highlight end of its dynamic range due to the nature of digital sensors (keyword "exposing to the right" – see https://en.wikipedia.org/wiki/Exposing_to_the_right for technical background)
As an example, when I scan negatives with Hasselblad's/Imacon's Flextight scanner, I get a histogram in the preview scan of the negative that shows the scanner's dynamic range and the tones of the negative fall somewhere inbetween. For very thin negatives the histogram is shifted towards the right/bright side, for very dense negatives it is shifted to the left/dark side (as it should be), without ever clipping or touching the borders (the scanner's dynamic range is larger than the tonal range that can be on the negative). Considering the nature of digital sensors, it would seem like the scanner would catch most tonal information if the histogram of the negative is spread out over as wide the dynamic range of the scanner as possible, or if it peaks towards the bright side of the histogram. A very dense negative's tones are spread out over only a very small part of the scanner's dynamic range/histogram, which on top of that is the dark part that contains less tonal separation - which seems like a bad idea.
There's probably some flaw in my way of thinking and it is driving me crazy that I can't wrap my head around it! – maybe you know where I am wrong? Is a dense negative bad for scanning?
P.S: Bonus question to those who know more about the workings of the Flextight/Imacon scanner in particular (could not find an answer in their manual): Does it make a qualitative difference if I scan a negative using the whole dynamic range the scanner provides me (setting white and black point to 0 and 255 during scanning, respectively) and then setting the white and black point I actually want for my image in post-processing, compared to setting that white/black point BEFORE scanning in the scanner software?
It seems to me that all that setting the white and black point before scanning does is, technically, making the scanner scan at full dynamic range anyway and then clipping/remapping the tones according to my settings in post - so basically the same as above.