Jarin, It seems to me that you have all the required data. I don't have a full answer but like to send you a free pdf with it when you send a request to rwlambrec@gmail.com. For now, Yes,8lp/mm covers people with good vision.Even 7lp/mm would do that.Hi all:
I apologize if this is covered very often, and this is a very subjective topic, but I'm missing the equation to decide upon a functioning circle of confusion for a specific set of parameters.
For larger prints, I don't fully trust my loupe when judging depth of field on a grainy ground glass that is stopped-down and dim, so for confirmation, I obtained one of the seemingly better depth of field apps for the field. In order for the app to function with any accuracy, I need to input the acceptable circle of confusion in microns. Here are my parameters:
I want to be able to enlarge 8x10" negatives to 32x40" (4x)
I want sharpness maintained at as close as 9" viewing distance (for those who care to look).
I want to resolve 8 lines/mm for those with good vision (is this a good figure?).
I shoot FP4 developed in a metol-pyro developer, and use Apo Sironar S optics between f/20 and f/45.
For 4x enlargement, I have already figured that diffraction limits me to f/45 or wider apertures. I am just missing a reliable DoF component. I will be purchasing a laser measurement tool as well to aid in wider scenes.
Thank you!
-Jarin
That's correct. I should have posted this attached table earlier.You can't directly measure your acceptable circle of confusion. You calculate it backwards from existing acceptable prints.
I recommend to stick with lp/mm;hope you get something from the pdf I've sent you.So, after perusing the Wikipedia article (if it is to be believed), it seems I should use a CoC of 40 microns / .04mm. My figuring is below, with one important question:
1.) At 25cm viewing distance, supposedly good vision can distinguish 5 line pairs/mm, which is a CoC of .2mm according to the wikipedia article. However, should this not instead be .1mm? Don't you need two CoCs to make a line pair? If you can distinguish 5 line pairs, isn't that the same as 10 lines?
2.) Anyway, for now let's go with .2mm CoC equivalent at 25cm viewing distance. I want to afford a little extra scrutiny for audiences like myself, so figured a .16 CoC which puts viewing distance at 20.83cm (8.2").
3.) I will be enlarging 4x, so .16mm on the print divided by 4 is .04mm on the film (40 microns).
...or should it really be .02mm (20 microns), since we deal in line pairs?
Unfortunately I have to save serious darkroom rentals (the 8x10 enlarger) for real printing only, and can't find this answer through extensive testing. I have to just go by a conservative formula until the first major project.
Jarin
Jarin google for 'point spread'function' to get your answer and search for a book called'Clarity' You'll enjoy it.Dan: Your math makes sense, but as there are 1000 microns in a millimeter, you mean 30 microns, no?
What won't stop snagging me is how a line pair equals the equivalent CoC. Shouldn't we need a CoC to resolve a line, therefore two CoCs are needed per line pair?
Ralph: thanks for the document. I can take a focused (whoops) look later today.
Jarin
So, after perusing the Wikipedia article (if it is to be believed), it seems I should use a CoC of 40 microns / .04mm. My figuring is below, with one important question:
1.) At 25cm viewing distance, supposedly good vision can distinguish 5 line pairs/mm, which is a CoC of .2mm according to the wikipedia article. However, should this not instead be .1mm? Don't you need two CoCs to make a line pair? If you can distinguish 5 line pairs, isn't that the same as 10 lines?
2.) Anyway, for now let's go with .2mm CoC equivalent at 25cm viewing distance. I want to afford a little extra scrutiny for audiences like myself, so figured a .16 CoC which puts viewing distance at 20.83cm (8.2").
3.) I will be enlarging 4x, so .16mm on the print divided by 4 is .04mm on the film (40 microns).
...or should it really be .02mm (20 microns), since we deal in line pairs?
Unfortunately I have to save serious darkroom rentals (the 8x10 enlarger) for real printing only, and can't find this answer through extensive testing. I have to just go by a conservative formula until the first major project.
Jarin
great reference thanksHi Jarin,
Going by the CoC formula in the Wikipedia article, one should input the anticipated viewing distance and enlargement factor, in addition to your personally desired print resolution, specified in lp/mm (line pairs per millimeter).
Reading the post I've quoted, above, it looks as if you're letting the formula dictate your closest anticipated viewing distance - putting the cart before the proverbial horse. Adults with healthy vision can typically focus no more closely than 25 cm (about 10 inches). That's why 25 cm has long been the so-called "standard viewing distance" when discussing resolution in terms of lp/mm (vs. angular resolution, expressed in arc-minutes, where distance is irrelevant.)
THX, the people who provide specs for theaters, both commercial and home theaters, fit their viewing distance calculations to an assumed maximum human acuity of 1.0 arc-minute, which equates to 6.88 lp/mm at a viewing distance of 25cm. Double the viewing distance and you can go to 3.44 lp/mm, yet still deliver 1.0 arc-minute of angular resolution.
Many photographic texts, however, including John B. Williams' Image Clarity: High Resolution Photography, consider 8 lp/mm to be the maximum resolution of healthy human vision at the standard viewing distance of 25cm. Of course, it varies from person to person, but I once read that eagles can resolve 24 lp/mm at 25cm, so I think it's safe to assume that most humans are limited to less than 10 lp/mm.
8 lp/mm at 25cm is equivalent to 0.86 arc-minute of angular resolution. I really suspect THX is rounding up from 0.86 to 1.0 arc-minute to make their theater calculations a little easier, but the net impact of that rounding, if indeed it was a conscious decision to round up to the nearest integer, is that they are telling people to sit a lot closer to their 1080p flatscreen TVs (and twice as close, still, to their 4k flatscreens) than they would if THX would acknowledge that we can resolve 0.86 arc-minute (8 lp/mm at 25cm) instead of only 1.0 arc-minute (6.88 lp/mm at 25cm).
Reading between the lines, it sounds as if you anticipate (or desire to support) a minimum viewing distance of 25cm (the closest distance at which healthy eyes can typically focus), a 4x enlargement factor and a desired print resolution of 5 lp/mm at 25cm.
Running the equation...
Max. permissible on-film CoC (mm) = viewing distance (cm) / desired final-image resolution (lp/mm) for a 25 cm viewing distance / enlargement / 25
CoC (mm) = 25 / 5 / 4 / 25 = 0.05 mm <--- Try this in your DoF calculations.
Note that if somebody views your print at a distance of 40 cm (15.75 inches) instead of 25 cm (9.84 inches), they will perceive a resolution equivalent to viewing an 8 lp/mm print at 25cm. It's only if they can focus more closely than 25cm and choose to do so, that they will perceive subject detail at something less than the equivalent of 5 lp/mm viewed at 25cm. And frankly, it's more likely that people will be looking at a 32x40-inch print from distances greater than 25cm. So... 5 lp/mm is probably "critical enough" for a 4x enlargement when your final print dimensions are that large.
Regarding your concern for the ratio of line pairs to CoCs, there are many references which say that a 0.2 mm CoC at the film or sensor equates to 5 lp/mm prior to enlargement. There are several texts that say CoC, prior to enlargement, is the reciprocal of the lp/mm you will record on film or at the sensor, or lp/mm is the reciprocal of the maximum CoC diameter you permit via DoF calculations and adherence to those calculations.
If, for example, you anticipate an 8x enlargement to produce 8x12-inch prints from a 35mm negative, 5 lp/mm at the print requires 40 lp/mm at the negative and thus, you must perform your DoF calculations with a maximum permissible in-camera CoC diameter of 1/40 = 0.025mm. The reciprocal of 40 lp/mm is roughly 0.03 mm. Sound familiar? Many people are disappointed with DoF calculators that use 0.03mm CoCs for 35mm format. They need to increase their desired print resolution from 5 lp/mm to 8 lp/mm, for example, and do the DoF calculations to limit on-film CoC diameters to the reciprocal of 8 lp/mm or 0.125 mm (but it's really tough to achieve 64 lp/mm on-film to deliver 8 lp/mm in an 8x enlargement, except with the likes of Tech Pan and some very good glass.
One last tip: Once you've calculated the maximum permissible CoC diameter for a specified viewing distance, enlargement factor and desired print resolution in lp/mm, you can calculate the f-Number at which diffraction will just begin to inhibit your desired print resolution as follows:
Max f-Number = CoC / 0.00135383
Warning: This formula only works if you've used the Wikipedia CoC equation (above) that takes into account your desired print resolution, viewing distance, and enlargement factor.
Thus, for an in-camera CoC diameter of 0.05 mm, you can stop down to 0.05 / 0.00135383 = 36.9, or about f/32 + 1/3 stop without concern for diffraction inhibiting your print resolution goal of 5 lp/mm in a 4x enlargement to be viewed at 25cm.
How was that constant 0.0013583 derived? Search for it on this page: http://www.faqs.org/faqs/rec-photo/lenses/tutorial/
OK, I'm rambling, but I hope that helps.
Mike
... can't find this answer through extensive testing. I have to just go by a conservative formula until the first major project.
Jarin
be aware that there is a subjective print improvement with higher resolutionYou may not be able to resolve above 8lp/mm but,15 lp/mm may still look cleaner to your eye. I is suggested that up to 25lp/mm can be appreciated subjectively.Thank you everybody! Especially Mike with his comprehensive response (how long did that take you!?) and Ralph with the very detailed document you emailed me.
I’ve settled on 8 lp/mm for 32x40 prints, which puts my CoC at .031mm (31 microns, or 32 lp/mm). From the most conservative figures I’ve seen, I have to shoot at 32 2/3 or wider to prevent degradation from diffraction.
I always walk up and lean into very big prints to see if I can relish in close details; I’d like to provide this opportunity in my own prints. Broad and close inspection are both important.
I can make contrast prints at home; I’m going to eventually test see if I can recognize a difference between 8 and 10 or 15 lp/mm when I really get close to the prints. 8x10 contacts may require a higher standard.
J
Thank you everybody! Especially Mike with his comprehensive response (how long did that take you!?) and Ralph with the very detailed document you emailed me.
I’ve settled on 8 lp/mm for 32x40 prints, which puts my CoC at .031mm (31 microns, or 32 lp/mm). From the most conservative figures I’ve seen, I have to shoot at 32 2/3 or wider to prevent degradation from diffraction.
I always walk up and lean into very big prints to see if I can relish in close details; I’d like to provide this opportunity in my own prints. Broad and close inspection are both important.
I can make contrast prints at home; I’m going to eventually test see if I can recognize a difference between 8 and 10 or 15 lp/mm when I really get close to the prints. 8x10 contacts may require a higher standard.
J
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