reciprocity for bergger bpf 200 shot @100

toddstew · Nov 15, 2005

Does anybody have any experience with reciprocity failure with bergger bpf 200 shot at 100asa? If so, do you happen to know the correction times? Or can someone direct me to the times?
Thanks,
Todd

jandc · Nov 15, 2005

toddstew said:
Does anybody have any experience with reciprocity failure with bergger bpf 200 shot at 100asa? If so, do you happen to know the correction times? Or can someone direct me to the times?
Thanks,
Todd

To 1/2 second - no adjustment

1 second - 1.5 stops

10 seconds - 3 stops

100 seconds - 4 stops

toddstew · Nov 15, 2005

thanks jandc. Pardon my dumb question, but how would that transfer to time? 1.5 stops equals how much time increase if I want to keep the same f-stop? Would 10 seconds become 30 seconds?

TheFlyingCamera · Nov 16, 2005

toddstew said:
thanks jandc. Pardon my dumb question, but how would that transfer to time? 1.5 stops equals how much time increase if I want to keep the same f-stop? Would 10 seconds become 30 seconds?

each additional stop is a doubling of the time - so yes, 10 becomes 30 seconds.

toddstew · Nov 16, 2005

Thank you for the illumination(yuk,yuk)
Todd

Jim Noel · Nov 18, 2005

Oops ther is a math error here.
If the exposure is 10 seconds a simple calculation would be 40 seconds (10x2=20;20x2=40)
However, I believe you will find that amount of time insufficient because the reciprocity for 40 seconds now comes into play. 3 stops is 2 raised to the third power, or 8. At the very least then, the time requirted would be 80 seconds.
To find out for sure, make 3 exposure, one at 40 seconds, one at 80 and one at 160 seconds. These are one stop apart and yuo will learn a lot about the reciprocity of the film. In fact, if you have a densitometer you will have enough information to make a graph of the reciprocity curve from which you can calculate the reciprocity for any given amount of time.

toddstew · Nov 21, 2005

thanks jim, I'll try it.

chrisofwlp · Mar 1, 2007

Jim Noel said:
Oops ther is a math error here.
If the exposure is 10 seconds a simple calculation would be 40 seconds (10x2=20;20x2=40)
However, I believe you will find that amount of time insufficient because the reciprocity for 40 seconds now comes into play. 3 stops is 2 raised to the third power, or 8. At the very least then, the time requirted would be 80 seconds.
To find out for sure, make 3 exposure, one at 40 seconds, one at 80 and one at 160 seconds. These are one stop apart and yuo will learn a lot about the reciprocity of the film. In fact, if you have a densitometer you will have enough information to make a graph of the reciprocity curve from which you can calculate the reciprocity for any given amount of time.

Opps one more math error. A ten second second exposre increased by three stops results in an 80 second exposure. Metered timeX2^number of stops=correct exposure. 10x2^3=80. This formula almost never fails.

Christopher Breitenstein

bruce terry · Mar 1, 2007

Am I crazy? Look at ilford's hp4 reciprocity specs here>http://www.ilfordphoto.com/Webfiles/2006216115141521.pdf. A metered 10 secs is recommended to be adjusted to about 30 seconds. According to their chart this mean "times 3" ... not a quantum ride of additional 3 "stops", or 10>20>40>80 sec.

Haven't done dark light above 8 seconds metered, but about x3, or 24 sec of exposure works fine at that level of the curve. Sure would like to know how far out in left field and/or lucky I am!! ;]

Bruce

reciprocity for bergger bpf 200 shot @100

Membership Council

Privacy & Transparency

Privacy & Transparency