Good morning, StereoKodak;
Well, I am not sure that I would phrase it as "taking a photograph of a photograph." We are dealing with a couple of different things here. When taking a photograph, there is the scene out there, and the image of the scene focused by the lens on the sensitized silver-bromide crystals in the emulsion on the film are altered by the light reflected from the scene falling on those crystals. The more light, the greater the effect or number of crystals that are affected. When we "develop" the film, we wash out the nonaffected silver-bromide crystals leaving an image on the transparent film layer that carries the emulsion, and the resulting image varies inversely to the light intensity of the original scene; the lighter parts in the scene are the darker or perhaps black parts on the developed film or "negative," and the darker parts in the scene are the lighter parts on the negative. The developed negative has an "inverted image."
While an enlarger used to make a print from the negative does involve all of the basic things used in taking a photograph, the path the light takes is different. You might say that the light source is inside the camera, and it passes through the negative with the amount of light being attenuated by the darker areas of the negative, and attenuated less by the lighter areas of the negative. This still inverted image of the negative is focused on the paper below by the lens of the enlarger, and the same effect on the silver-bromide crystals in the print paper emulsion happens by the light falling on it in the same way that the light from the original scene affected the emulsion layer of the film. Again, the greater amount of light falling on the paper surface affects more of the silver-bromide crystals in the emulsion on the surface of the paper, just as it did with the film. However, this time we are dealing with a "negative" image of the original scene, so when we go through the developing process with the print paper, we again reverse the sense of the image and the dark areas in the negative image become the light areas in the developed image on the paper, and the light areas become the dark areas on the paper. We have "reversed" the image again so that it looks like the original scene to our eyes.
As mentioned, in several ways, the chemistry is very similar, yes, but the light path is different and the way that the light is affected is different. That is the main reason why I have difficulty in saying that printing and enlarging is just "taking a photograph of a photograph."
Does that sound reasonable, or have I just confused things even more?
Enjoy; Ralph, Latte Land, Washington