..why do you need to know this?
In the negative I think the answer is none?How many dyes were in the Technicolor process?
If you still can, you may wish to add this to the original post.To be clear I am only interested in end product after development. i.e. How many dyes exist in a developed negative.
To the contrary:The mask is present when coated. It is not formed during the process.
There are 3 main dyes, C/M/Y, but they differ having come from up to 9 or even more different couplers and can form slightly different dyes to trim the final image to give the best color reproduction.
These couplers would be the primary C/M/Y couplers, the 2 or more DIR couplers, the 2 or more masking couplers and a few others for good measure. The mask is present when coated. It is not formed during the process.
PE
Ted, this shows basic ignorance on the way any modern colour film is madeup.
Why then do you insist on precise numbers of couplers employed and not guesses?
To the contrary:
The mask is just formed by processing, imagewise.
Before processing there is just a uniform hue to the film, due to the coloured couplers. But this is no mask yet.
Fascinating PE, a follow on question... Asking my original question in a slightly different way, if I had a developed colour negative of step wedge (i.e. and image representative of all possible densities). From a chemical perspective would I end up with something like the following?
1. A compound for the red layer (cyan dye) actually possible three possible compounds
2. A compound for the green layer (magenta dye) actually possible three possible compounds
3. A compound for the blue layer (yellow dye) actually possible three possible compounds
4. Two compounds of what ever is remaining in the mask, that has not been removed because there is no density in the corresponding layers that the mask is intended to correct for.
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