How many color dyes are used in a single colour negative film?
Say porta 160 is it just four? a dye each for the red green and blue layers plus one dye for the colour coupler? or is there two colour coupler dyes? or two dyes for different densities for the red sensitive layer? etc etc.
In the kodak suite of colour negative films how many different dyes are used across the product lines? e.g. do modern films share the same dyes, all or some etc?
..why do you need to know this? Is the colored coupler already colored at it's time of dispersion into the film, or does it only gain color after chromogenic development when it reacts with the oxidised part of the color developer? Just like the other three couplers do. The dyes produced by chromogenic development are spectrally quite imperfect so it probably wouldn't be a good idea to have multiple dyes where one would do. How many dyes were in the Technicolor process? Not a chromogenic process - but should give you a clue.
When conducting research, facts are very useful Facts are useful when making tests and building calibrated equipment and software based on assertions...
To be clear I am only interested in end product after development. i.e. How many dyes exist in a developed negative.
There are 3 main dyes, C/M/Y, but they differ having come from up to 9 or even more different couplers and can form slightly different dyes to trim the final image to give the best color reproduction.
These couplers would be the primary C/M/Y couplers, the 2 or more DIR couplers, the 2 or more masking couplers and a few others for good measure. The mask is present when coated. It is not formed during the process.
not to mention some films have a "4th colour layer" which one would assume may have a slightly different dye set produced.
some folks develop their film with "the wrong" developer, which MAY produce a slightly different Dye than the factory intended. ANd every Version of a given film may have revisions. (ever notice a digit like 6 beside the film name on the cartridge.?)
The mask is just formed by processing, imagewise.
Before processing there is just a uniform hue to the film, due to the coloured couplers. But this is no mask yet.
There are 3 main dyes, C/M/Y, but they differ having come from up to 9 or even more different couplers and can form slightly different dyes to trim the final image to give the best color reproduction.
These couplers would be the primary C/M/Y couplers, the 2 or more DIR couplers, the 2 or more masking couplers and a few others for good measure. The mask is present when coated. It is not formed during the process.
Fascinating PE, a follow on question... Asking my original question in a slightly different way, if I had a developed colour negative of step wedge (i.e. and image representative of all possible densities). From a chemical perspective would I end up with something like the following?
1. A compound for the red layer (cyan dye) actually possible three possible compounds
2. A compound for the green layer (magenta dye) actually possible three possible compounds
3. A compound for the blue layer (yellow dye) actually possible three possible compounds
4. Two compounds of what ever is remaining in the mask, that has not been removed because there is no density in the corresponding layers that the mask is intended to correct for.
Well If one does not wish to remain ignorant then a possible remedy is to ask questions and have them answered with facts, otherwise someone is likely to be ill informed...
As PE already indicated, next to the sensitizing and imageforming dyes, which number already may differ due to sub-layers, there are also various accessory dyes. Thus you would get a different number for most films.
The mask is just formed by processing, imagewise.
Before processing there is just a uniform hue to the film, due to the coloured couplers. But this is no mask yet.
Fascinating PE, a follow on question... Asking my original question in a slightly different way, if I had a developed colour negative of step wedge (i.e. and image representative of all possible densities). From a chemical perspective would I end up with something like the following?
1. A compound for the red layer (cyan dye) actually possible three possible compounds
2. A compound for the green layer (magenta dye) actually possible three possible compounds
3. A compound for the blue layer (yellow dye) actually possible three possible compounds
4. Two compounds of what ever is remaining in the mask, that has not been removed because there is no density in the corresponding layers that the mask is intended to correct for.