I use the "Na2" method for my printing, buying the solutions from B&S.
As described by B&S, the solution I use to coat the paper is made up of
“Palladium Solution No 3” (palladium hexachloropalladite, where Pd ion has a valence of +2).
“Ferric Oxalate Solution No 1” (ferric oxalate 27%).
“Sodium platinum (Na2)” 5 %, diluted from a 20% solution (gold hexachloroplatinate, where Pt ion has a +4 valence).
My question: Is the final image made entirely of palladium, or is there also some contribution from the platinum in the Na2? Tetravalent Pt {in dihydrogen hexachloroplatinate (IV)} was found by Willis to be very poor at creating an image, but does Pt contribute to the image in this case, even if in a very small amount? Basically, should my prints be described as "palladium prints", "Pt/Pd" prints, or "Pd/Pt prints"? Has anyone done XRF analysis of this type of print?
I understand that there is a discussion of this method in the second edition of the Arentz book, and perhaps this is covered there; but the book, being out of print, is frightfully expensive in Amazon and e-Bay.