alanrockwood
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I am contemplating and idea, and it would depend in part on have at least some light being transmitted through the most dense part of the negative....Why do you need to kow this?
log d 5 = ND5 = 16 2⁄3 stops = 0.001% transmittanceI am contemplating and idea, and it would depend in part on have at least some light being transmitted through the most dense part of the negative.
Thanks for the comment. Yes, I know how density adds up. It's basically the same as what as known as the Beer-Lambert law in spectroscopy. Absorption (basically density) is additive. Transmission is multiplicative. The reason is the logarithmic relationship between density and transmission.Sounds right.
Hey alanrockwood you know density adds up. If you put two pieces of film on top of each other, and each has a 3.0 density. The two add up to a density of 6.0
Not sure what you are planning, but that might come in handy.
Under relatively normal illumination/exposure (including those parts of the negative that received the highest dose of light) and relatively normal development the maximum density tends to not exceed 3 for a film like Tri-X.
Sounds right.
Hey alanrockwood you know density adds up. If you put two pieces of film on top of each other, and each has a 3.0 density. The two add up to a density of 6.0
Not sure what you are planning, but that might come in handy.
Sure, it's not going to be a quality image forming light path (so you won't want to do this to make a "filter") but densities add up that way.Just to clarify, if I took a bracketed series of blank shots, ie. exposure but no detail, I could stack the negatives to give me the nd I want.
I'd rather not reinvent the wheel if I don't have to. Thanks for posting your findings.So why don’t you develop an overexposed strip of film and read the density and tell us what you find?
I get with Kodak TMX 5052 135 leader strip a 3.16 density with both an X-Rite 301 and an Ihara T5 densitometers. Developed HC-110 Dil B.
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