Just a thought; shouldn't the "size of print" above be replaced by "size of enlargement". If printing full frame they are of course the same, but not with a selective enlargement.David A. Goldfarb said:For photographic purposes, it is conventional to use the linear magnification factor, so the magnification factor would be the size of the print along one dimension divided by the size of the negative along the same dimension. So if 6x7cm is nominally 2-1/4x2-3/4", the magnification factor for an 8x10" print could be computed as 10/2.75=3.6X magnification.
George Collier said:........If you are after relative exposures, though, I like the idea of measuring relative neg stage to easle plane distances (change to bulb distance is the material issue, I think), I'm gonna try it next time.
Dave Miller said:No confusion Tom, that is the system that I use, with the slight difference that I measure from lens to easel surface to the nearest centimeter.
One more way to skin the cat - measure the size of the neg holder opening (always stays the same). When you get the magnification you want, measure the uncropped image at the easle plane. Should give accurate image enlargement ratio, I think(works for me). If you are after relative exposures, though, I like the idea of measuring relative neg stage to easle plane distances (change to bulb distance is the material issue, I think), I'm gonna try it next time.
Magnification adjustment factors are only of interest if you wish to change your enlargement size without producing a second test print(s). Negative size is irrelevent.
I have a Beseler 23C XL II, printing 6x7 cm with an 80mm Rodagon.
Does anyone know what the "factors" are for 11x14, 16x20 & 20x24?
Thanks.
The OP is making color prints. Probably he is using a diffusion enlarger.the internal components of the lamp house (most importantly the distance between the lamp and the negative) wrongly remains fixed in position when they (or it) should be changing (lengthening or shortening) with a change in magnification.
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