Suppose that you want a portrait that encompasses 600mm from left to right at the subject plane to be mapped onto the roughly 195.5mm minor dimension of an 8 x 10 film with a 480mm lens.
That requires a subject distance (subject to first nodal point) of about p = 1953mm. This is a Thin-Lens-Equation estimate and could be made accurate if we knew both the nodal distance and flange distance of the lens.
Disregarding the unknown nodal distance and flange distance of your lens and assuming that the nodal points are likely relatively close to each other and that the flange distance is similar to the nodal distance, the lens board would need to be roughly 636mm forward of the film in this case. This is about 25 and is close to the estimate in post #2.
If the lens board is large enough you might solve the problem by building a box-type extension lens board to place the lens 200mm to 300mm forward of the lens board receiver. Then you should have sufficient bellows in reserve for close focusing when wanted without overstretching the bellows.
Just out of curiousity, say that I knew the nodal points and the flange focus. How would these factor into the calculation? I've never see these accounted for in any calculation.
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