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how many stops is .6 ND filter?

ToddB

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Hey guys,

Co-worker let me borrow a ND filter. it says .6 on the ring. How many stops is that?

Todd
 
That's a 2-stop reduction.

0.3 = 1-stop
0.6 = 2-stop
0.9 = 3-stop

And so on...

Ken
 
If you're curious about why, those are in log-2 notation.

2 log 2 = 0.602
3 log 2 = 0.903
 
Actually, they are log-base-10, or "D". A 1.0D has 10x attenuation, a 2.0D has 100x attenuation, an nD is 10n; in this case 0.6D = 100.6 = 3.98x. Stops are log-2, i.e. 4 stops is 24 = 16x attenuation.

To convert from D to stops, you do this:

stops = log2(10D)
stops = D / log10(2) = D / 0.301

in this case, stops = 0.6 / 0.301 = 1.993 = 2 stops. This is what you'd expect from above, because 3.98x attenuation is pretty much 4x, and 4x is 2 stops.
 
Thanks guys, I have it on my F4, so I'm assuming camera metering will auto compensate for the filter?
 
Then just a quick use of that meter would have given you that answer without any math...
 
every 0.3 equal 1 stop,because the log of 2 is roughly 0.3;photomath is soo much fun.I wish they would have used it in highschool;then,i'm sure I would have paid much better attention.

What!! Did someone say math??

Groan...not again.
 
Thar's 3 kinds of people on this world. Thems that kin do math, and thems that cain't.


The math is good but the American English is wrong.

It should read: Thems whut kin do math and thems whut cain't