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High-end lenses for 4x5 enlarging

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Michael Firstlight

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I'm planning to enlarge up to 30x40 from 4x5 both B&W and color. I have an LPL 4550 XLG (both VCCE and Dicro modules). I'm curious as far as very high-end enlarging lenses go, I currently have a 150mm Componon-S and a 135mm Componon-S. For prints 20x24 to 30x40, how much better/sharper would a lens such as a Componon 120mm APO HM MC or a Rodagon-G 150mm be over my current Componon-S lenses? I even wonder if there are any Rodagon-G 150mm lens available - they seem extremely rare and never seem to come up for sale on eBay.

Mike
 
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Ian C

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The best lens to use for a particular job is one that was designed specifically for the intended format and the magnification range that you intend on using.

A good standard-type lens used within its specified range will give excellent results. A specialized high-magnification lens used significantly outside of its intended magnification range won’t give superior results, possibly not as good as a standard len used within its intended range.

For a projection to fully cover the 30” x 40” print format requires somewhat more than 8.5X magnification of the approximately 95 mm x 120 mm image rectangle recorded on a 4” x 5” negative.

Two lenses that I’m familiar with are the 135 mm f/5.6A and 150 mm f/5.6A EL Nikkor enlarging lenses. These are 6-element 4-group Double Gauss design. They give excellent results in my experience. The 135 mm lens is rated in the Nikon data as having a usable magnification range of 2X – 5X – 10X (minimum – optimum – maximum). The 150 mm is rated at 2X – 4X – 8X. Both will work well for 30” x 40” enlarging, but the 135 mm version is rated up to 10X and so, might be the better choice. It also requires less projection distance than a 150 mm lens.

http://www.galerie-photo.com/manuels/el-nikkor-enlarging-lenses.pdf

I also have a 4/150 APO Rodagon N (2X – 6X – 15X), and 5.6/150 Rodagon G (10X – 20X – 40X). Magnification-wise, the APO Rodagon N is good choice for 30” x 40” prints from a 4” x 5” negative. These are expensive and, now, hard-to-find. The 150 Rodagon G is even scarcer. I don’t think of this as good choice for making a 30” x 40” print from a 4” x 5” negative due to the magnification mismatch.

http://www.prograf.ru/rodenstock/enlarging_en.html

At or slightly above 8.5X I don’t see any real difference in image quality between the EL Nikkors, Rodagon, APO Rodagon N, and Componon-S lenses (I own 135 mm and 150 mm Componon-S lenses). If you want to pay a high price, then the APO Rodagon will satisfy. If you buy it and expect noticeably superior results at 8.5X compared to a standard lens (EL Nikkor, Rodagon, Compnon-S, and so forth) you won’t see it—unless you have a good imagination. The Rodagon G is intended for larger work and isn’t particularly suitable for this magnification.

You said that you already have the 135 mm and 150 mm Componon-S enlarging lenses. These give perfect results. You already own some of finest lenses made for 4” x 5” enlarging.
 
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Michael Firstlight

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You said that you already have the 135 mm and 150 mm Componon-S enlarging lenses. These give perfect results. You already own some of finest lenses made for 4” x 5” enlarging.

Yeah, I think for 30x40 the 135mm Componon-S will be fine. Usually a 120mm lens isn't for 4x5 as there is too much fall-off, but the Componon 120mm APO HM MC I see is specifically designed for upto 4x5 and I can find no information if that specific lens would suffer any fall-off since it specifically lists upto 4x5 as a supported format. Yah, it isn't cheap, but I was wondering if at 30x40 if the sharpness difference of the Componon 120mm APO HM MC would be obvious from my 135mm Componon-S. My new 14x14 darkroom under construction as part of the new home that is currently under construction (due to complete in April) has 9 foot ceilings and with the 4550XLG able to reverse the head on the column I'll expect to be easily able to do floor project on a 30x40 vacuum easel I picked up for a song a few months ago. Maybe even the 150mm would be sufficient with all that height.

Thanks,
Mike
 
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