maverickaesthetics
Member
While I've been printing with various alternative processes for a number of years and have read many books, reading through my just received copy of Don Nelson's (fantastic) book on Kallitype, VDB and Argyrotype brought up a question that I hadn't previously considered.
The book is very well illustrated and contains a lot of comparisons regarding paper and toners and how they play with the different processes. One of the attributes that's always listed, is exposure scale (ES) for both, toners as well as papers.
Since I often print kallitypes (which I develop with sodium citrate), I looked closely at the table listing dmax and ES for the different toners. I'm mostly printing on Hahnemühle Platinum Rag (HPR). In Don's book, the dmax on HPR for kallitypes developed with sodium citrate is 1.42 and (for example) borax is a much lower 1.33. However, the ES behaves the exact opposite: 1.9 for sodium citrate and 2.7 for borax. That initially confused me.
From my (admittedly limited) understanding, ES is defined as how many steps a given process can reproduce on (for example) a Stouffer stepwedge between paper white and pure dmax. So, in essence, it is a measure of contrast - high ES representing a low contrast and low ES representing a very contrasty print.
Here comes my question: with analog negatives, ES seems a very important piece of information for the process, since the negative has to be exposed and developed to cater to the limitations of the process. But with digital negatives, is ES really an important factor? If we do a proper linearisation, we do compensate for the shortcomings of the process, don't we? If we have a process with a long ES (say, salt printing), then we print a negative with very dense highlights and the curve takes care of the rest, making sure the tones between dmax an paper white land in the right spot. Now, I can see that it might be easier to linearise for a process with a long ES (if you can print a dense enough negative) since the density variations on the negative between tones are greater, but in theory, it should be possible to linearise both perfectly: processes with small and large ES. And only dmax really counts to expand the 'scale' of a print.
However, my understanding of this might be completely wrong. If so, please forgive my ignorance. I would like to hear some insights into this from people way more experienced than me. In the past, I've just glossed over the mentioning of ES, but re-reading some of the books in my bookshelf (and Christina Anderson's fantastic new paper chart on alternativephotography.com), the term seems to be omnipresent. But does it only really matter for analog negatives, or does it equally apply to digital negatives?
Thanks for any insights,
Jo
The book is very well illustrated and contains a lot of comparisons regarding paper and toners and how they play with the different processes. One of the attributes that's always listed, is exposure scale (ES) for both, toners as well as papers.
Since I often print kallitypes (which I develop with sodium citrate), I looked closely at the table listing dmax and ES for the different toners. I'm mostly printing on Hahnemühle Platinum Rag (HPR). In Don's book, the dmax on HPR for kallitypes developed with sodium citrate is 1.42 and (for example) borax is a much lower 1.33. However, the ES behaves the exact opposite: 1.9 for sodium citrate and 2.7 for borax. That initially confused me.
From my (admittedly limited) understanding, ES is defined as how many steps a given process can reproduce on (for example) a Stouffer stepwedge between paper white and pure dmax. So, in essence, it is a measure of contrast - high ES representing a low contrast and low ES representing a very contrasty print.
Here comes my question: with analog negatives, ES seems a very important piece of information for the process, since the negative has to be exposed and developed to cater to the limitations of the process. But with digital negatives, is ES really an important factor? If we do a proper linearisation, we do compensate for the shortcomings of the process, don't we? If we have a process with a long ES (say, salt printing), then we print a negative with very dense highlights and the curve takes care of the rest, making sure the tones between dmax an paper white land in the right spot. Now, I can see that it might be easier to linearise for a process with a long ES (if you can print a dense enough negative) since the density variations on the negative between tones are greater, but in theory, it should be possible to linearise both perfectly: processes with small and large ES. And only dmax really counts to expand the 'scale' of a print.
However, my understanding of this might be completely wrong. If so, please forgive my ignorance. I would like to hear some insights into this from people way more experienced than me. In the past, I've just glossed over the mentioning of ES, but re-reading some of the books in my bookshelf (and Christina Anderson's fantastic new paper chart on alternativephotography.com), the term seems to be omnipresent. But does it only really matter for analog negatives, or does it equally apply to digital negatives?
Thanks for any insights,
Jo