Ira Rush
Member
Enlargement sizes and aspect ratios for the numerically impaired
OK, so Im not a math Geek!
I understand aspect ratios, and how to calculate them.
I understand that for instance 35mm film would have an aspect ratio of 1:1.5 (35mm frame is 24mm in height x 36mm in width, which then equates to a ratio of 36/24 = 1.5).
I understand that an 8x10 sheet of paper would have a aspect ratio of 1.25, (obviously 1.5 is larger than 1.25), and if you wanted to fill the entire 8" x 10" paper with an image, some cropping will necessarily occur at one end or the other, or both.
Taking that same 35mm negative and this time using a 16x20 sheet of paper (aspect ratio of again 1.25) cropping would occur here too.
Now, what I dont understand is how the following is calculated .
35mm film has a format ratio of 1:1.5, so a full-frame print on 16"x20" paper can measure no more than 13.33"x20", otherwise the image would be significantly cropped.
And this
If we take a full frame 35mm negative and enlarge it to make an 8x10" print, we enlarge the long dimension of the negative to match the long dimension of the paper and it results in a print measuring 6.6" wide
How are those precise sizes calculated (13.33 and 6.6)?
Is there some formula to calculate these sizes and to know what the actual width and height of the enlarged print would be?
Thanks in advance
OK, so Im not a math Geek!
I understand aspect ratios, and how to calculate them.
I understand that for instance 35mm film would have an aspect ratio of 1:1.5 (35mm frame is 24mm in height x 36mm in width, which then equates to a ratio of 36/24 = 1.5).
I understand that an 8x10 sheet of paper would have a aspect ratio of 1.25, (obviously 1.5 is larger than 1.25), and if you wanted to fill the entire 8" x 10" paper with an image, some cropping will necessarily occur at one end or the other, or both.
Taking that same 35mm negative and this time using a 16x20 sheet of paper (aspect ratio of again 1.25) cropping would occur here too.
Now, what I dont understand is how the following is calculated .
35mm film has a format ratio of 1:1.5, so a full-frame print on 16"x20" paper can measure no more than 13.33"x20", otherwise the image would be significantly cropped.
And this
If we take a full frame 35mm negative and enlarge it to make an 8x10" print, we enlarge the long dimension of the negative to match the long dimension of the paper and it results in a print measuring 6.6" wide
How are those precise sizes calculated (13.33 and 6.6)?
Is there some formula to calculate these sizes and to know what the actual width and height of the enlarged print would be?
Thanks in advance