Remember, you must use a filter to block the "visible" light, otherwise the "visible light" will overpower any IR effect (and lower EI without a filter will basically over-expose your film).
Yes, smaller aperture (larger f-number on the lens) is lower/slower EI _if_ the shutter speed is not changed.
For example, consider an initial exposure of f=11 and shutter speed=1/125:
- Then f-8 and shutter=1/125, your EI is one stop lower.
- Or, f-11 and shutter= 1/60, your EI is also one stop lower.
- However, if f-8 and shutter=1/250, your EI is the same.
(Quick, somebody check my math.)
Basically, to get the desired exposure, you want a certain amount of light hitting the film. You make sure you get the correct amount by adjusting your f-stop and shutter speed.
Each change in f-number on the lens is one stop. Roughly speaking, each larger number (smaller aperture hole) lets in half as much light. Each smaller number (larger aperture hole) lets in twice the light.
Each change in shutter speed is one stop. Roughly speaking, each faster step (higher shutter speed) lets in half as much light. Each slower step setting lets in twice as much light.
Nearly any filter reduces the total amount of light, so you need to compensate when setting the EI manually. Also, from what I've read, IR wavelengths are not as, shall we say, strong (or perhaps near IR film is not as sensitive to IR as it is to "visible" light), so even more exposure may be warranted in addition to compensating for the IR filter factor.
I hope I got all of that right.