Howdy all,
I have here a confounded set of calculations that could benefit from your looking over. Rude-Golberg would be fond of such a "proof", and it is born from my lack of densitometer and a desire to waste as little film as I can in making exposure tests.
What I'm looking to do is copy a 4x5" slide to b&w film by contact under my enlarger, ultimately with tri-color filters to make separation negatives.
I'm able to take an incident reading of the light at the baseboard (EV 1.66), and I'm trying to determine how much light, on average, the slide will block, and consequently how much extra exposure to give above the incident reading (figured from f/1 and EV 1.66 on an exposure table).
The slide I have in mind is low contrast (overcast day) and exposure was on the money, so I can safely assume that it's within the dmin/dmax, or on the straight line portion.
The straight-line portion of Kodak EPP appears to have a density range of ≈ 0.66 to 2.75 (http://www.kodak.com/global/en/professional/support/techPubs/e113/e113.pdf).
So, if I turn the density into opacity, using D=logO, I get about 4.6 and 562 O for 0.66 & 2.75 D respectively.
This is effectively my "filter factor", is it not? So that 4.6 equates to about 2 stops and 562 to about 9 stops, for an average of 5.5 stops.
Is there anything obviously amiss with my calculations or assumptions?
Thanks in advance
I have here a confounded set of calculations that could benefit from your looking over. Rude-Golberg would be fond of such a "proof", and it is born from my lack of densitometer and a desire to waste as little film as I can in making exposure tests.
What I'm looking to do is copy a 4x5" slide to b&w film by contact under my enlarger, ultimately with tri-color filters to make separation negatives.
I'm able to take an incident reading of the light at the baseboard (EV 1.66), and I'm trying to determine how much light, on average, the slide will block, and consequently how much extra exposure to give above the incident reading (figured from f/1 and EV 1.66 on an exposure table).
The slide I have in mind is low contrast (overcast day) and exposure was on the money, so I can safely assume that it's within the dmin/dmax, or on the straight line portion.
The straight-line portion of Kodak EPP appears to have a density range of ≈ 0.66 to 2.75 (http://www.kodak.com/global/en/professional/support/techPubs/e113/e113.pdf).
So, if I turn the density into opacity, using D=logO, I get about 4.6 and 562 O for 0.66 & 2.75 D respectively.
This is effectively my "filter factor", is it not? So that 4.6 equates to about 2 stops and 562 to about 9 stops, for an average of 5.5 stops.
Is there anything obviously amiss with my calculations or assumptions?
Thanks in advance
