Hi,
I have 1 old metal case of DEKTOL (Net Wt 1 LB 4 Oz *to make 1 U.S Gallon or 3,8 liters).
My question is how many grams of this for make 1 liters working solition (1+9)
Please tell me how to calculate?
Thank you,
George
You don't want to do that.... Dektol powder is a compound - meaning mixture of different chemicals. If you divide it, there is no guarantee you get the same ratio of component chemicals. If you insist on doing it, you'll want to shake it up really well randomly first for best chance at getting it well mixed.
Dektol stock solution is typically used 1+1, 1+2 or maybe 1+3, 1+2 being the most common, but never 1+9.
Also, it is recommended not to split the raw chemical into portions, because it is a mixture of several chemicals, and the mixture is not necessarily homogeneous. You are better off taking it all and making 3.8 liters of Dektol.
After you have it mixed to make one gallon, divide it into smaller bottles. Fill them to the top and seal the bottles tightly. Store them in a cool dark place, and use as needed. Dektol is best used at 1+2, sometimes 1+1 or 1+3.
What everyone else id saying over and over, don't split it up, and 1+9? I use it at 1+3 to process film at the same times as D-76, 1+9 would take a really long time!
forever lol, I think they have gone through at least 2 different pouch designs so far.
Yes and it is better to make it all at once and top bottles to the brim for storage. weighing out dry components wont work as the mix will ultimately have heavier elements settle on the bottom.
Well, if you had said, "won't work perfectly", I'd agree
I picked up a 5 gal foil pack from a closed-up camera store, and frugally measure out 150g/L. The dry chemical is a dull beige color, rather than white (as fresh Dektol should be), and I did mix the crap out of it. I only use it for casual, non-archival prints, and it works fine for that purpose.