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Print a series of 3-step step wedges (X+d, X, X-d) each with a "d" lower by a factor (say 2: 20%, 10%, 5%, 2.5%, etc.) Then find the (dmin) where the 3 steps are no longer statistically distinguishable with desitometer (or visually.) Repeat the same with several values of X - one each for shadows, mid-tones, and highlights, for example. The printing method that gives the lowest dmin is the most continuous. Obviously, here the assumption is that each method is perfectly linear.
What wavelength are you using to make your measurements? .... Density at a wavelength unrelated to the action spectra of the process you intend to use it for is meaningless.
The reason that folks found that some colored pigments were better for printing negatives is the fact that some colored pigments are better at blocking UV light better than the black pigments. Thus one could deposit less of a colored ink onto the plastic and get the more light blocked that you could with the black pigment.
I don't believe your quest has much practical value. If an inkjet printer can print a ramp in which you cannot discern banding, it is good enough for alternative processes. The tonal scale of most alt processes is narrower than that of silver prints or regular inkjets. In other words, you can print fewer perceptible differences in tone. If there's banding in the negative but it's imperceptible, it will produce an even more imperceptible banding in the print.
Thank you! That's a really good definition, and it works for my problem. I made two step table negatives, one CMYK grayscale and one colorized grayscale. I plotted transmission density vs. digital tone (K) . At any tone t, the curve with the greater slope has more continuous tone. So while color gives consistently higher density over most of the tonal scale, color has areas where tone is less continuous, making it less useful (and possibly even harmful). In the plot below, the slope of the color negative curve is nearly flat around 45% and again around 65%. In these areas, there is almost no differentiation of tone. Using step tables with more steps shows that in these problem areas density becomes highly irregular and even reverses.
I'd like to understand what is causing this behavior. All I can come up with is this: the density of a color negative has two components, one physical and one optical (spectral). In the midtones of the negative, where the color is purest, optical density overwhelms physical density and creates these anomalies. Optical density tapers off toward the highlights and shadows of the negative. A grayscale negative shows only the effect of physical density.
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Not sure I fully understand the difference between CMYK grayscale and colorized grayscale. How are they produced...starting with a step wedge of R=G=B? or gray mode? and then how are they sent to the printer. Any icc profile used? Also in the chart is the label "color" is for colorized grayscale and "grayscale" is for the CMYK grayscale?
A little confusion on my part....
:Niranjan.
It is confusing, and maybe I've added to the confusion. I wish there was standard terminology for this.
Assume we're printing a step table, and assume the Photoshop document in Gray Gamma 2.2. Since the image is a step table, it does not need to be inverted.
If we send this image to the printer and specify Color (not B&W) the printer will make neutral tones by mixing C,M,Y, and K ink. The resulting print is what I may have called "CMYK grayscale" to distinguish it from a grayscale negative made with black ink only, which you would get if you chose B&W in the printer settings (not a good idea).
To make a colorized grayscale negative, we convert the document to Adobe RGB, then add color. The original Burkholder (1999) method was to do a Fill -> Color with the Fill operation in Color mode. The way I would do it today would be to add a Color Fill layer in Color mode. Some people use Screen mode.
If instead of a step table you were printing a real image, you would invert before colorizing.
There is another method of colorizing that is used by the "Easy Digital Negatives" (EDN) system, and I believe it explains why colorized negatives remain popular. EDN colorizes by applying a gradient map over the image (or the inverted image). The "stops" of the gradient attempt to shape the printer curve so that it's closer to linear. It's an elegant idea, but it suffers from "continuity" problems in the midtones. As tnp61 pointed out, it's not going to make much difference in a typical alt process print. But a mathematical model chokes on inversions.
I wanted to understand the history of digital negative making, and so I found a used copy of Burkholder's 1999 book on eBay. Back then, everyone was making negatives with imagesetters. But affordable inkjet printers were becoming available, and he talks about his experience using them. This is where he explains his decision to make colorized negatives, rather than CMYK grayscale negatives: colorized gives you equal density with less ink, but not as good coverage (it was Burkholder who distinguished between "physical density" and "spectral density"). By 2013 (his "Inkjet Companion" book) he had abandoned color and gone back to CMYK grayscale. A grayscale printer curve (transmission density vs. digital tone) is a thing of beauty, even on my "K1" printer.
I use your printer settings (see below) !!
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The way I do that is by specifying Printer Manages Color in PS, on one hand and then specifying No Color Management the printer driver as usual. This can also be done using Adobe Color Printing Utility (ACPU.)
:Niranjan.
Niranjan,I have started making my digital negatives without icc profile recently which anecdotally seemed to give me correction curves that are less "jumpy." The way I do that is by specifying Printer Manages Color in PS, on one hand and then specifying No Color Management the printer driver as usual. This can also be done using Adobe Color Printing Utility (ACPU.)
:Niranjan.
My results (see below) support Doug Gray's conclusion. Here's what I did:By the way, here is the link to the work of Doug Gray over at Luminous Landscape (someone whose quantitative work I respect a lot) that shows that the methods #2 and #3 should give identical outputs.
:Niranjan.
The Method 2 and 3 curves are nearly identical. Method 1 (my method, Photoshop manages color) gives a more irregular curve and introduces greater image distortion in the shadows and midtones (i.e., the corrections are more severe).
Here's another test comparing the "null transform" method (printer manages color, no color adjustment) with ACPU. For this experiment, I merged measurements from a much more elaborate set of step tables (see the image in the last post), so I'm confident in the numbers.
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