I don't know about that. But if you are using D-23 1:9, I can't imagine what you are doing about the developer capacity situation. You must be mixing up a gallon to develop a single 35mm roll
I have been using D-23 1+9 with 0.5g/l lye added to restore the required alkalinity to good effect.
If I wanted to further dilute - in hopes of establishing even greater acutance - is there a fairly straightforward way to calculate the required increase in NaOH, short of measuring with a pH meter and adding lye until it hit the magic number?
Instead of further dilution, I'd suggest you first try reducing your agitation. Assuming you're agitating every minute, try agitating only every third minute (keep the same time for a first test, but be prepared to extend your development further, as lower agitation will often slow the overall process). A side effect of this reduced agitation is that shadows will develop more than highlights (due to local exhaustion) giving a compensating effect (nice for preserving details in clouds when exposing for the land on a landscape, for instance).
You could even stretch to agitating every five minutes, but that's unlikely to gain anything noticeable over three minutes.
As we know D-23 1+14 with 2.5 g/l Sodium Carbonate is nearly the same as Crawley's FX-1 (without the homeopathic addition of Iodide). So you may want to give D-23 1+14 with 0.5g/l Lye a chance and increase Lye in small amounts (0.1g) at a time if there is underdevelopment.
I was curious about this question...I found this somewhere...but can't validate it's accuracy. I believe the sweet spot for edge effect for D23 is 9.5ish with development to exhaustion. Phenodine, I have read, can enhance the edge effects when added in very small amounts to Metol. I have seen this in the form of Mackie lines when using FX2 agitating 10 seconds per 2 minutes for 20 min dev time.
If you add 1 mg NaOH to 1.0 L of water you will increase the pH
What will the pH be ?
Molar mass NaOH = 40 g/mol
Mol NaOH = 0.001 g / 40 g/mol = 0.000025M
[OH-] = 0.000025 M
pOH = - log 0.000025
pOH = 4.60
pH = 14.00 - 4.62
pH = 9.38
Calculation refers to absolutely pure H2O totally free of any dissolved substances including CO2
I found it...https://www.quora.com/How-much-NaOH-is-needed-to-increase-the-pH-of-water.. ALSO CORRECTION...Not Phenodine but Glycine and Metol... I got that confused.
The calculation is easy enough to follow but I still have questions I need to explore:
- If the calculation above is correct, then my use of 0.5g/l of NaOH seems like real overkill
- I would love to see the derivation of this calculation rather than just the mechanical maths
Not asking you for that, just ruminating on what I need to go understand. Thanks again.
My 0.5g/l would deliver a pH of 12.1 in liter of pure water.
Buy you're not adding this to pure water -- your solution is already alkaline due to the sodium sulfite, so in fact you're creating a buffer system of sorts; your pH will be somewhere between that of original D-23 (8+?) and your sodium hydroxide reference at 12+. I don't know the chemistry math well enough, but you've got 100/10 = 10 g/L of sodium sulfite and 0.5 g/L of sodium hydroxide -- someone ought to be able to calculate the pH (without the metol) of that buffer...
The interesting question now becomes: Would reducing the amount of NaOH (or Sodum Carbonate) to get the pH down to the "9.5-ish sweet spot" better promote edge effects, I wonder. That is, am I currently too alkaline to see those effects in a pronounced way?
If only it would be so simple. Equilibrium reactions will balance the pH at some point that you cannot predict linearly like this. AFAIK there's no "layman's approach" to theoretically predicting the pH of a fairly complex mixture like a photographic developer. The feasible alternative is to get some pH strips or a pH meter and just do it experimentally.Ach ... right. I'll see if I can figure this out but I suspect you have to take the molar weights and proportion of each alkaline component and add them to reach the actual final pH.
No idea where this 9.5 is sweet spot for edge effects came from. At pH of 9.5, dilutions 1+9 and 1+14 will result in very severe underdevelopment.
You get quite deep in the weeds here because the word acutance has two meanings, the gradient at a knife edge measured with a microdensitometer and also the apparent visual sharpness including both the gradient and the adjacency effect.P212-214 here:
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