Gerald Koch said:
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By using a minus red filter only the short wave lengths of the visible spectrum, the blue and green portions, will reach the film. Those colors will appear lighter while the other colors of the spectrum, the longer wavelength yellows and, oranges will appear darker with red showing as black. Of course, how well this works depends on how good the filter is in cutting off the longer wavelengths. No filter is perfect but this should produce a very good approximation of the ortho look.
My reponse was directed to someone who contended that the converse of what you stated was possible.
My position is that one can not filter and duplicate a true panchromatic material from an orthochromatic material. A great deal depends on the spectral characteristics of the emulsion.
Orthochromatic materials are sensitive to the blue spectrum and may have very little if any sensitivity to red. So therefore by shutting of the blue spectrum with a minus blue filter does not necessarily equate to making an orthochromatic material into a panchormatic material. If the sensitivity to the red spectrum is not present as a characteristic of the emulsion, no amount of filtering, regardless of the filter used is going to create emulsion sensitivity that does not exist.
Thus I stand with my earlier position that removal of something does not equate to the creation or the addition of something that is not present as an emulsion characteristic.
As we both know, panchromatic emulsions have a more global sensitivity then orthochromatic materials. As I stated originally that was not what I was addressing. My original statement addressed the mistaken belief that one could filter orthochromatic materials and have them replicate a panchromatic emulsion. Since orthochromatic materials have a limited spectral response, there is no amount of filtering that will effect a spectral change to the extent that they replicate panchromatic materials.
For those that may be interested, I direct them to the chart of spectral response found it Adams "The Negative" This chart may be found on page 22.