Question:
Is it possible to replace C41 developer with some kind of B&W developer, then bleach and fix and still get usable color negatives? I'm looking for ways to make color developing as inexpensive as possible. Maybe I'll do some of my own experimenting, providing someone doesn't tell me "It's impossible."
Although the developer system of this invention has been illustrated with respect to black and white photosensitive material, it may also be used as the first developer step in a color photosensitive meratial. Although not wishing to be bound by theoretical explanations, it is felt that the hydroquinone component of the first developer gives contrast to the image produced by the action of the Metol or equivalent amine reducing agent, and the sodium sulfite serves as both a preservative for the solution and a solvent for silver halides.
Is there anything that can be added to a B&W developer that reacts with the film and forms the dyes? What would adding CD-4 or somesuch to an existing developer do?
Is there anything that can be added to a B&W developer that reacts with the film and forms the dyes? What would adding CD-4 or somesuch to an existing developer do?
True enough, but its always more fun to make things than to buy them.
CD4 turns the B&W developer into a pseudo color developer.
In addition, dyes formed from CD4 are less stable.
PE
Is there anything that can be added to a B&W developer that reacts with the film and forms the dyes? What would adding CD-4 or somesuch to an existing developer do?
After googling some MSDSs for kodak color developer, I'd assume that the developing agent in kodak's developer is 4-(N-ethyl-N-2-hydroxyethyl)-2-methylphenylenediamine, correct? That isn't all that different from CD-2, which is, according to the data sheet from the photographer's formulary, 4-N, N-Diethyl-2-methylphenylenediamine. What is it about this, and other chemicals like CD-4, cause dyes to form?
It seems like the similarity between the color developers I've been able to find (and rodinal) is NH2, something that "normal" B&W developers, like hydroquinone and phenidone, lack. By this logic, would amidol (2,4-diaminophenol) have the same (or maybe better?) dye-forming effect as rodinal (4-aminophenol), due to the presence of twice as many amines?
Am I on to something or am I merely thinking that I'm beginning to understand something because I have very basic chemistry knowledge and wikipedia?
HRST has said it correctly as to usage and cost.
Your comments are close here but no cigar! A proper color developer has one NH2 and one NR2 group. This is the combination that forms dyes most properly. Other developers may contain OH and NH2 and form weak transient dyes, but they do not really count in the real world.
Now, to go on, the R groups must be correct for the couplers or the wrong dyes form or the dyes that do form have the wrong stability.
PE
So essentially any B&W developer can be used as the developer for colour processes? Why is C-41 developer made of completely different chemicals that don't appear in any B&W developer, then?
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