Helen B said:Jorge,
I'm glad that at least one person agrees with me!
I've also noticed that the base adds a uniform level of difference between the UV and visual readings (UV density being higher than visual, as Jorge's readings) - but this does not, of course, alter the relative exposure values. So in the case where the UV and visual relative densities (relative step to step) are the same, it should not matter whether UV or visual is used - the curve is just shifted along the x-axis. (I couldn't think of a concise enough way to describe this 'relatively neutral' aspect of base plus silver when I wrote my previous posts, so lazily used 'neutral'.)
In that case (the UV and visual densities of the step wedge being uniformly different) it would not matter which mode was used unless the densitometer was out of calibration. Then it may be better to measure the step wedge in the mode in which you were going to measure the film density because then the calibration error would partially cancel - the curve would be stretched or compressed diagonally, but would maintain the same general shape. Note that the error would not be cancelled entirely.
So, if your UV and visual density step wedge measurements are different by a non-constant value there is either something wrong with your densitometer or the density steps in your step wedge are not neutral. It is acceptable for the base not to be neutral, as long as it is uniform.
The preferable way to avoid errors caused by the possible non-neutrality of the step wedge is to have a calibrated densitometer, and to measure the step wedge in the mode that most closely resembles the way the film will be exposed (usually visual) then to measure the image of the step wedge on film in the mode that most closely resembles the way in which the paper (or next stage in the process) will be exposed.
How does that sound?
Best,
Helen
Helen B said:Jorge,
The preferable way to avoid errors caused by the possible non-neutrality of the step wedge is to have a calibrated densitometer, and to measure the step wedge in the mode that most closely resembles the way the film will be exposed (usually visual) then to measure the image of the step wedge on film in the mode that most closely resembles the way in which the paper (or next stage in the process) will be exposed.
How does that sound?
Best,
Helen
Helen B said:Thanks Sandy. I'll be interested to hear his reply.
Regards,
Helen
gainer said:My densitometer has adjustments for both slope and intercept. I designed it that way. I calibrate it to read density of film by setting the slope to read two points on the step density wedge. Now that is a problem if the spectral transmission of the wedge is different from that of the film. In fact, there are so many such problems that I do not put a great deal of faith in densitometer readings for estimating printing exposure. Still, they are good for comparative analyses of film and developer combinations, and give an estimate of contrast index that is good enough for government work, so I can tell what grade of paper or filter I need.
Helen B said:First: change the filters in your densitometer. Look through the Wratten curves, or Melles Griot or whoever, and, in the best engineering tradition, take a WAG at the filters that would most closely resemble the two ends of the VC papers response (filter method A'). The printing filters themselves wont do, because they could pass wavelengths that the paper is not sensitive to but a combination of one or two other filters (that would correspond to the overall spectral sensitivity of the paper) with the printing filters might be worth investigating ('filter method B'). Swap out your two least favourite filters for these and produce calibration curves. Those Status M filters arent good for much anyway*.
Measure the step wedge image on film using those two filters. Interpolate for the intermediate curves (method A) or produce a series of curves over the range of printing filters (method B).
Print the step wedge using a series of printing contrasts. You now have two sets of corresponding curves.
If you are going to use the densitometer readings to estimate exposure and contrast grade of a printing material required to make a full scale print of a negative, the only frequency response that matters is that of the photosensor in the final readings. It must match that of the printing material.Kirk Keyes said:Patrick - you are right that the spectrum of the light should not matter with a properly designed densitometer. That's basic physics. No where does the color of the light come into the equations. The ratio of the incident light and the transmitted light (or reflected for reflection density) are the only thing that matter. But note that we are taking about light as an unchanging property.
The problem I was addressing and JMoore was indirectly asking about is what happens when the spectrum of the light is changing between the inital exposure of the material, the reading of the processed material, and the subsequent exposure of yet another material. Then the changes in color spectrum do matter.
Kirk
Kirk Keyes said:Patrick writes: ... It must match that of the printing material."
Here's another example - say we are going to test IR film and then print it onto Platinum paper.
We know that our IR film, because we are going to use a 87 filter (which blocks all visible light and passes IR above about 740 nm), needs to be exposed to IR light only. Do we mesure the step wedge with the densitometer set to UV - no. Do we use it set to visible - no. We must match the filtration of our densitometer to the spectral sensitivity our our film, and the color spectrum of light that we will be exposing that film.
Ed Sukach said:I'm just a tad confused. I would think that once the film is developed, the original exposure spectrographic response would have very little to do with anything in printing.
The strength of the light that will affect the printing material at a given wavelength will be all that is important.... and that will be a product of the enlarging lamp; transmission properties of the enlarging lens (I have found slight lens-to-lens variations); and the processed film, acting as a dichroic filter.
Donald Miller said:Ed,
Your thoughts would be accurate insofar as conventional developers. With proportional staining developers such as ABC and Pyrocat the matter becomes murky. The reason is that the color of the proportional stain has an effect on the transmission of light. This is dependant on the color of light that the print is exposed to.
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