This is a question for those of you into the Beutler formula, and that have a copy of Willi Beutlers reference book Meine Dunkelkammer Praxis.
In my copy of the book (6th edition), he first of all provides the formula for what is known today as Beutlers high accutance developer (page 33 Neue Kleinbildfilme). In the book, the formula is provided as a certain mix of some base-solutions that he describes at the beginning of the book (page 16 Stammlösungen), but both in terms of resulting stock solution and working solution, this is identical to the Beutlers formula described
(there was a url link here which no longer exists) in apug.org.
This is all fine. However, at the end of the same chapter (page 36), Willi Beutler described how he filled a mix of 250ml stock solution A and 250ml stock solution B on to 20 bottles of 25ml, which he then later used one such bottle to mix with 475 ml water for a 500ml working solution. My German is a bit rusty, but I cannot understand this. The original Beutler formula results in a consentration of 1 gram metol per liter working solution. Doing it the way he describes with the 25ml bottles, would result in a consentration of only 0,25 gram metol per liter working solution. Are my maths wrong (or perhaps my understanding of German), or is there some mis-typing in Willi Beutlers otherwise good reference book?
In my copy of the book (6th edition), he first of all provides the formula for what is known today as Beutlers high accutance developer (page 33 Neue Kleinbildfilme). In the book, the formula is provided as a certain mix of some base-solutions that he describes at the beginning of the book (page 16 Stammlösungen), but both in terms of resulting stock solution and working solution, this is identical to the Beutlers formula described
(there was a url link here which no longer exists) in apug.org.
This is all fine. However, at the end of the same chapter (page 36), Willi Beutler described how he filled a mix of 250ml stock solution A and 250ml stock solution B on to 20 bottles of 25ml, which he then later used one such bottle to mix with 475 ml water for a 500ml working solution. My German is a bit rusty, but I cannot understand this. The original Beutler formula results in a consentration of 1 gram metol per liter working solution. Doing it the way he describes with the 25ml bottles, would result in a consentration of only 0,25 gram metol per liter working solution. Are my maths wrong (or perhaps my understanding of German), or is there some mis-typing in Willi Beutlers otherwise good reference book?