Beseler 8x10 drum gap

[AnselAdamsX]

I bought a Beseler 8x10 print drum that I intend to use to develop 4x5 film. It has the insert. I put a sheet of 4x5 in it to see how it fit. It has a pretty large gap between the film and the drum wall. I attached a picture showing the gap.
Is this correct? From what I read in other posts I thought the film would be touching the drum wall.

Thanks
Chris

 

[Bob-D659]

Looks about right, when I put a piece of 4x5 paper in the drum, there is an end gap of well over 4mm between the edge of the paper and the divider strip when I push the paper against the stop.

When it gets wet it will stick to the wall.

 

[Whiteymorange]

The gap looks about right to me, and it's never been a problem.

 

[mikecnichols]

I can't find an appropriate thread for this without starting a new one, but I have a problem with my 8x10 drum. Two questions, I have three 11x14 drums and will use one of them to develop as I need to do some today ASAP.

First question, would I still use 60ml for ONE 8x10 in the 11x14 drum or should I use 120ml? Second question, is it possible to repair the front cap of the drum if it has become separated? Physically, I can definitely fix it, but would the glue that it would take contaminate the incoming chemicals?

 

[Ian C]

For drums of the same type and diameter, the required solution volume is proportional to length.

Suppose the solution volume of the 8” x 10” drum is v1 and the solution volume of the 11” x 14” drum is v2, and the lengths are L1 = 8” and L2 = 11”.

V2/V1= L2/L1, so

V2 = (L2/L1)*V1


If V1 =60ml, then

V2 = (11/8)*60ml = 82.5ml

The glue, once fully set, shouldn’t react with the water solution of the processing solution. Getting a glue that forms a strong, waterproof repair of plastic is sometimes problematic.

 

[mikecnichols]

For drums of the same type and diameter, the required solution volume is proportional to length.

Suppose the solution volume of the 8” x 10” drum is v1 and the solution volume of the 11” x 14” drum is v2, and the lengths are L1 = 8” and L2 = 11”.

V2/V1= L2/L1, so

V2 = (L2/L1)*V1


If V1 =60ml, then

V2 = (11/8)*60ml = 82.5ml

The glue, once fully set, shouldn’t react with the water solution of the processing solution. Getting a glue that forms a strong, waterproof repair of plastic is sometimes problematic.

Thank you for the quick reply! That is great information....thank you!