5stringdeath
Member
Philisophically, it represents every image that ever hit the sensor.
Think about that.
you guys need your own thread please. Way Off Topic.
Think about that.
you guys need your own thread please. Way Off Topic.
The sensor array is not altered. It captures a charge that remains only for the length of time that the photons are in those little 'buckets'. Once the light leaves, the charge also dissipates. There is no latent 'image' on the sensor.
At some point in time the sensor will lose its ability to recognize the charge or capture it but that point of alteration does not represent a single image.
Friend, let me give you an honestly well-meant tip for life:
The ignorant should not condescend to people who know something about the subject at hand.
I'm pretty sure I've never been in a Ritz, but I do have advanced degrees in the software arena and write digital camera firmware for fun in my spare time (when I'm not printing images from my Diacord in the bathroom with homebrew developers).
Please explain to me what the meaningful difference is between storing a latent image by accumulating electrons in silicon as opposed to silver?
I'll refrain from adding an ad-hominem here, as appealing as it is given your obdurate obscurantism... whoops, there I went.![]()

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