I'm mixing a formula that contains 5g sodium bisulfite as a buffer to hydroquione. I don't have bisulfite but I do have metabisulfite. Is this apples and oranges or is there a conversion?
Why do you say that? When dissolved in water, metabisulfite forms bisulfite ion and they are the same thing. In amateur darkroom formulae I doubt anyone ever used pure sodium bisulfite in dry form as an ingredient; it's a misnomer.
When Kodak sold chemicals a mixture of sodium bisulfite and sodium metabisulfite was sold as sodium bisulfite. If you look at the MSDS for sodium bisulfite it is listed as 58 - 99% sodium bisulfite and 0 - 42% sodium metabisulfite. Pure sodium bisulfite is sold as a 40 - 45% solution rather than as a solid.
Kodak recommended using the same amount regardless of which chemical the formula mentioned.
There is no metabisulfite in solution. None we be
brewing. At crystallization two bisulfites join loosing
a molecule of water; so the meta. In solution the meta
joins with water; so two bisufites. The meta is more
concentrated by one molecule of water.
Likely there is a source for one and/or the other.
The ph in solution is that of the bisulfite. Dan
Not that it matters a lot in terms of darkroom mixology, but this is simply untrue. In concentrated solution of sodium bisulfite, metabisulfite is present.
"None we be brewing" I did qualify my statement.
Besides you and I know better. Concentrated
solution or not, as a species metabisulfite
will exist at ten to the minus who knows
how many zeros. Dan